Simplify (4a^2h^2-8a^3h+3a^4)÷(2a^2)

$(4 a^{2} h^{2} - 8 a^{3} h + 3 a^{4}) \div (2 a^{2})$

Step 1

Rewrite the division as a fraction.

$\frac{4 a^{2} h^{2} - 8 a^{3} h + 3 a^{4}}{2 a^{2}}$

Step 2

Simplify the numerator.

Factor $a^{2}$ out of $4 a^{2} h^{2} - 8 a^{3} h + 3 a^{4}$ .

Factor $a^{2}$ out of $4 a^{2} h^{2}$ .

$\frac{a^{2} (4 h^{2}) - 8 a^{3} h + 3 a^{4}}{2 a^{2}}$

Factor $a^{2}$ out of $- 8 a^{3} h$ .

$\frac{a^{2} (4 h^{2}) + a^{2} (- 8 a h) + 3 a^{4}}{2 a^{2}}$

Factor $a^{2}$ out of $3 a^{4}$ .

$\frac{a^{2} (4 h^{2}) + a^{2} (- 8 a h) + a^{2} (3 a^{2})}{2 a^{2}}$

Factor $a^{2}$ out of $a^{2} (4 h^{2}) + a^{2} (- 8 a h)$ .

$\frac{a^{2} (4 h^{2} - 8 a h) + a^{2} (3 a^{2})}{2 a^{2}}$

Factor $a^{2}$ out of $a^{2} (4 h^{2} - 8 a h) + a^{2} (3 a^{2})$ .

$\frac{a^{2} (4 h^{2} - 8 a h + 3 a^{2})}{2 a^{2}}$

Factor by grouping.

For a polynomial of the form $a x^{2} + b x + c$ , rewrite the middle term as a sum of two terms whose product is $a \cdot c = 3 \cdot 4 = 12$ and whose sum is $b = - 8$ .

Reorder terms.

$\frac{a^{2} (3 a^{2} + 4 h^{2} - 8 a h)}{2 a^{2}}$

Reorder $4 h^{2}$ and $- 8 a h$ .

$\frac{a^{2} (3 a^{2} - 8 a h + 4 h^{2})}{2 a^{2}}$

Factor $- 8$ out of $- 8 a h$ .

$\frac{a^{2} (3 a^{2} - 8 (a h) + 4 h^{2})}{2 a^{2}}$

Rewrite $- 8$ as $- 2$ plus $- 6$

$\frac{a^{2} (3 a^{2} + (- 2 - 6) (a h) + 4 h^{2})}{2 a^{2}}$

Apply the distributive property.

$\frac{a^{2} (3 a^{2} - 2 (a h) - 6 (a h) + 4 h^{2})}{2 a^{2}}$

Move parentheses.

$\frac{a^{2} (3 a^{2} - 2 a h - 6 a h + 4 h^{2})}{2 a^{2}}$

Factor out the greatest common factor from each group.

Group the first two terms and the last two terms.

$\frac{a^{2} ((3 a^{2} - 2 a h) - 6 a h + 4 h^{2})}{2 a^{2}}$

Factor out the greatest common factor (GCF) from each group.

$\frac{a^{2} (a (3 a - 2 h) - 2 h (3 a - 2 h))}{2 a^{2}}$

Factor the polynomial by factoring out the greatest common factor, $3 a - 2 h$ .

$\frac{a^{2} ((3 a - 2 h) (a - 2 h))}{2 a^{2}}$

$\frac{a^{2} (3 a - 2 h) (a - 2 h)}{2 a^{2}}$

Step 3

Cancel the common factor of $a^{2}$ .

Cancel the common factor.

$\frac{a^{2} (3 a - 2 h) (a - 2 h)}{2 a^{2}}$

Rewrite the expression.

$\frac{(3 a - 2 h) (a - 2 h)}{2}$

Simplify (4a^2h^2-8a^3h+3a^4)÷(2a^2)

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