Simplify (4x^-2)/(y^-8)

$\frac{4 x^{- 2}}{y^{- 8}}$

Step 1

Move $x^{- 2}$ to the denominator using the negative exponent rule $b^{- n} = \frac{1}{b^{n}}$ .

$\frac{4}{y^{- 8} x^{2}}$

Step 2

Move $y^{- 8}$ to the numerator using the negative exponent rule $\frac{1}{b^{- n}} = b^{n}$ .

$\frac{4 y^{8}}{x^{2}}$