Simplify ((6p^2+p-12)/(8p^2+18p+9))÷((6p^2-11p+4)/(2p^2+13p-7))

$\frac{6 p^{2} + p - 12}{8 p^{2} + 18 p + 9} \div \frac{6 p^{2} - 11 p + 4}{2 p^{2} + 13 p - 7}$

To divide by a fraction, multiply by its reciprocal.

$\frac{6 p^{2} + p - 12}{8 p^{2} + 18 p + 9} \cdot \frac{2 p^{2} + 13 p - 7}{6 p^{2} - 11 p + 4}$

Factor by grouping.

For a polynomial of the form $a x^{2} + b x + c$ , rewrite the middle term as a sum of two terms whose product is $a \cdot c = 6 \cdot - 12 = - 72$ and whose sum is $b = 1$ .

Multiply by $1$ .

$\frac{6 p^{2} + 1 p - 12}{8 p^{2} + 18 p + 9} \cdot \frac{2 p^{2} + 13 p - 7}{6 p^{2} - 11 p + 4}$

Rewrite $1$ as $- 8$ plus $9$

$\frac{6 p^{2} + (- 8 + 9) p - 12}{8 p^{2} + 18 p + 9} \cdot \frac{2 p^{2} + 13 p - 7}{6 p^{2} - 11 p + 4}$

Apply the distributive property.

$\frac{6 p^{2} - 8 p + 9 p - 12}{8 p^{2} + 18 p + 9} \cdot \frac{2 p^{2} + 13 p - 7}{6 p^{2} - 11 p + 4}$

Factor out the greatest common factor from each group.

Group the first two terms and the last two terms.

$\frac{(6 p^{2} - 8 p) + 9 p - 12}{8 p^{2} + 18 p + 9} \cdot \frac{2 p^{2} + 13 p - 7}{6 p^{2} - 11 p + 4}$

Factor out the greatest common factor (GCF) from each group.

$\frac{2 p (3 p - 4) + 3 (3 p - 4)}{8 p^{2} + 18 p + 9} \cdot \frac{2 p^{2} + 13 p - 7}{6 p^{2} - 11 p + 4}$

Factor the polynomial by factoring out the greatest common factor, $3 p - 4$ .

$\frac{(3 p - 4) (2 p + 3)}{8 p^{2} + 18 p + 9} \cdot \frac{2 p^{2} + 13 p - 7}{6 p^{2} - 11 p + 4}$

Factor by grouping.

For a polynomial of the form $a x^{2} + b x + c$ , rewrite the middle term as a sum of two terms whose product is $a \cdot c = 8 \cdot 9 = 72$ and whose sum is $b = 18$ .

Factor $18$ out of $18 p$ .

$\frac{(3 p - 4) (2 p + 3)}{8 p^{2} + 18 (p) + 9} \cdot \frac{2 p^{2} + 13 p - 7}{6 p^{2} - 11 p + 4}$

Rewrite $18$ as $6$ plus $12$

$\frac{(3 p - 4) (2 p + 3)}{8 p^{2} + (6 + 12) p + 9} \cdot \frac{2 p^{2} + 13 p - 7}{6 p^{2} - 11 p + 4}$

Apply the distributive property.

$\frac{(3 p - 4) (2 p + 3)}{8 p^{2} + 6 p + 12 p + 9} \cdot \frac{2 p^{2} + 13 p - 7}{6 p^{2} - 11 p + 4}$

Factor out the greatest common factor from each group.

Group the first two terms and the last two terms.

$\frac{(3 p - 4) (2 p + 3)}{(8 p^{2} + 6 p) + 12 p + 9} \cdot \frac{2 p^{2} + 13 p - 7}{6 p^{2} - 11 p + 4}$

Factor out the greatest common factor (GCF) from each group.

$\frac{(3 p - 4) (2 p + 3)}{2 p (4 p + 3) + 3 (4 p + 3)} \cdot \frac{2 p^{2} + 13 p - 7}{6 p^{2} - 11 p + 4}$

Factor the polynomial by factoring out the greatest common factor, $4 p + 3$ .

$\frac{(3 p - 4) (2 p + 3)}{(4 p + 3) (2 p + 3)} \cdot \frac{2 p^{2} + 13 p - 7}{6 p^{2} - 11 p + 4}$

Cancel the common factor of $2 p + 3$ .

Cancel the common factor.

$\frac{(3 p - 4) (2 p + 3)}{(4 p + 3) (2 p + 3)} \cdot \frac{2 p^{2} + 13 p - 7}{6 p^{2} - 11 p + 4}$

Rewrite the expression.

$\frac{3 p - 4}{4 p + 3} \cdot \frac{2 p^{2} + 13 p - 7}{6 p^{2} - 11 p + 4}$

Factor by grouping.

For a polynomial of the form $a x^{2} + b x + c$ , rewrite the middle term as a sum of two terms whose product is $a \cdot c = 2 \cdot - 7 = - 14$ and whose sum is $b = 13$ .

Factor $13$ out of $13 p$ .

$\frac{3 p - 4}{4 p + 3} \cdot \frac{2 p^{2} + 13 (p) - 7}{6 p^{2} - 11 p + 4}$

Rewrite $13$ as $- 1$ plus $14$

$\frac{3 p - 4}{4 p + 3} \cdot \frac{2 p^{2} + (- 1 + 14) p - 7}{6 p^{2} - 11 p + 4}$

Apply the distributive property.

$\frac{3 p - 4}{4 p + 3} \cdot \frac{2 p^{2} - 1 p + 14 p - 7}{6 p^{2} - 11 p + 4}$

Factor out the greatest common factor from each group.

Group the first two terms and the last two terms.

$\frac{3 p - 4}{4 p + 3} \cdot \frac{(2 p^{2} - 1 p) + 14 p - 7}{6 p^{2} - 11 p + 4}$

Factor out the greatest common factor (GCF) from each group.

$\frac{3 p - 4}{4 p + 3} \cdot \frac{p (2 p - 1) + 7 (2 p - 1)}{6 p^{2} - 11 p + 4}$

Factor the polynomial by factoring out the greatest common factor, $2 p - 1$ .

$\frac{3 p - 4}{4 p + 3} \cdot \frac{(2 p - 1) (p + 7)}{6 p^{2} - 11 p + 4}$

Factor by grouping.

For a polynomial of the form $a x^{2} + b x + c$ , rewrite the middle term as a sum of two terms whose product is $a \cdot c = 6 \cdot 4 = 24$ and whose sum is $b = - 11$ .

Factor $- 11$ out of $- 11 p$ .

$\frac{3 p - 4}{4 p + 3} \cdot \frac{(2 p - 1) (p + 7)}{6 p^{2} - 11 (p) + 4}$

Rewrite $- 11$ as $- 3$ plus $- 8$

$\frac{3 p - 4}{4 p + 3} \cdot \frac{(2 p - 1) (p + 7)}{6 p^{2} + (- 3 - 8) p + 4}$

Apply the distributive property.

$\frac{3 p - 4}{4 p + 3} \cdot \frac{(2 p - 1) (p + 7)}{6 p^{2} - 3 p - 8 p + 4}$

Factor out the greatest common factor from each group.

Group the first two terms and the last two terms.

$\frac{3 p - 4}{4 p + 3} \cdot \frac{(2 p - 1) (p + 7)}{(6 p^{2} - 3 p) - 8 p + 4}$

Factor out the greatest common factor (GCF) from each group.

$\frac{3 p - 4}{4 p + 3} \cdot \frac{(2 p - 1) (p + 7)}{3 p (2 p - 1) - 4 (2 p - 1)}$

Factor the polynomial by factoring out the greatest common factor, $2 p - 1$ .

$\frac{3 p - 4}{4 p + 3} \cdot \frac{(2 p - 1) (p + 7)}{(2 p - 1) (3 p - 4)}$

Cancel the common factor of $3 p - 4$ .

Factor $3 p - 4$ out of $(2 p - 1) (3 p - 4)$ .

$\frac{3 p - 4}{4 p + 3} \cdot \frac{(2 p - 1) (p + 7)}{(3 p - 4) (2 p - 1)}$

Cancel the common factor.

$\frac{3 p - 4}{4 p + 3} \cdot \frac{(2 p - 1) (p + 7)}{(3 p - 4) (2 p - 1)}$

Rewrite the expression.

$\frac{1}{4 p + 3} \cdot \frac{(2 p - 1) (p + 7)}{2 p - 1}$

Multiply $\frac{1}{4 p + 3}$ by $\frac{(2 p - 1) (p + 7)}{2 p - 1}$ .

$\frac{(2 p - 1) (p + 7)}{(4 p + 3) (2 p - 1)}$

Cancel the common factor of $2 p - 1$ .

Cancel the common factor.

$\frac{(2 p - 1) (p + 7)}{(4 p + 3) (2 p - 1)}$

Rewrite the expression.

$\frac{p + 7}{4 p + 3}$

Simplify ((6p^2+p-12)/(8p^2+18p+9))÷((6p^2-11p+4)/(2p^2+13p-7))

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