Simplify (-8i)(2i)

$(- 8 i) (2 i)$

Step 1

Multiply $(- 8 i) (2 i)$ .

Multiply $2$ by $- 8$ .

$- 16 i i$

Raise $i$ to the power of $1$ .

$- 16 (i^{1} i)$

Raise $i$ to the power of $1$ .

$- 16 (i^{1} i^{1})$

Use the power rule $a^{m} a^{n} = a^{m + n}$ to combine exponents.

$- 16 i^{1 + 1}$

Add $1$ and $1$ .

$- 16 i^{2}$

Step 2

Rewrite $i^{2}$ as $- 1$ .

$- 16 \cdot - 1$

Step 3

Multiply $- 16$ by $- 1$ .

$16$