Simplify (8x^4+2x^2-1)+(3x^3-5x^2+7x+1)

$(8 x^{4} + 2 x^{2} - 1) + (3 x^{3} - 5 x^{2} + 7 x + 1)$

Remove parentheses.

$8 x^{4} + 2 x^{2} - 1 + 3 x^{3} - 5 x^{2} + 7 x + 1$

Combine the opposite terms in $8 x^{4} + 2 x^{2} - 1 + 3 x^{3} - 5 x^{2} + 7 x + 1$ .

Add $- 1$ and $1$ .

$8 x^{4} + 2 x^{2} + 3 x^{3} - 5 x^{2} + 7 x + 0$

Add $8 x^{4} + 2 x^{2} + 3 x^{3} - 5 x^{2} + 7 x$ and $0$ .

$8 x^{4} + 2 x^{2} + 3 x^{3} - 5 x^{2} + 7 x$

Subtract $5 x^{2}$ from $2 x^{2}$ .

$8 x^{4} + 3 x^{3} - 3 x^{2} + 7 x$