Simplify (9a^3b+6ab-4)-(10a^3b-6a^2b^2-6)

$(9 a^{3} b + 6 a b - 4) - (10 a^{3} b - 6 a^{2} b^{2} - 6)$

Step 1

Simplify each term.

Apply the distributive property.

$9 a^{3} b + 6 a b - 4 - (10 a^{3} b) - (- 6 a^{2} b^{2}) - - 6$

Simplify.

Multiply $10$ by $- 1$ .

$9 a^{3} b + 6 a b - 4 - 10 (a^{3} b) - (- 6 a^{2} b^{2}) - - 6$

Multiply $- 6$ by $- 1$ .

$9 a^{3} b + 6 a b - 4 - 10 (a^{3} b) + 6 (a^{2} b^{2}) - - 6$

Multiply $- 1$ by $- 6$ .

$9 a^{3} b + 6 a b - 4 - 10 (a^{3} b) + 6 (a^{2} b^{2}) + 6$

Remove parentheses.

$9 a^{3} b + 6 a b - 4 - 10 a^{3} b + 6 a^{2} b^{2} + 6$

Step 2

Simplify by adding terms.

Subtract $10 a^{3} b$ from $9 a^{3} b$ .

$- a^{3} b + 6 a b - 4 + 6 a^{2} b^{2} + 6$

Add $- 4$ and $6$ .

$- a^{3} b + 6 a b + 6 a^{2} b^{2} + 2$