Simplify cube root of 7* cube root of 49

$\sqrt[3]{7} \cdot \sqrt[3]{49}$

Step 1

Combine using the product rule for radicals.

$\sqrt[3]{7 \cdot 49}$

Step 2

Write the expression using exponents.

Multiply $7$ by $49$ .

$\sqrt[3]{343}$

Rewrite $343$ as $7^{3}$ .

$\sqrt[3]{7^{3}}$

Step 3

Pull terms out from under the radical, assuming real numbers.

$7$