Simplify - fourth root of 16y^8

$- \sqrt[4]{16 y^{8}}$

Step 1

Rewrite $16 y^{8}$ as ${(2 y^{2})}^{4}$ .

$- \sqrt[4]{{(2 y^{2})}^{4}}$

Step 2

Pull terms out from under the radical, assuming positive real numbers.

$- (2 y^{2})$

Step 3

Multiply $2$ by $- 1$ .

$- 2 y^{2}$

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