Simplify n(n^2+2n-4)

$n (n^{2} + 2 n - 4)$

Step 1

Apply the distributive property.

$n \cdot n^{2} + n (2 n) + n \cdot - 4$

Step 2

Simplify.

Multiply $n$ by $n^{2}$ by adding the exponents.

Multiply $n$ by $n^{2}$ .

Raise $n$ to the power of $1$ .

$n^{1} n^{2} + n (2 n) + n \cdot - 4$

Use the power rule $a^{m} a^{n} = a^{m + n}$ to combine exponents.

$n^{1 + 2} + n (2 n) + n \cdot - 4$

Add $1$ and $2$ .

$n^{3} + n (2 n) + n \cdot - 4$

Rewrite using the commutative property of multiplication.

$n^{3} + 2 n \cdot n + n \cdot - 4$

Move $- 4$ to the left of $n$ .

$n^{3} + 2 n \cdot n - 4 \cdot n$

Step 3

Multiply $n$ by $n$ by adding the exponents.

Move $n$ .

$n^{3} + 2 (n \cdot n) - 4 \cdot n$

Multiply $n$ by $n$ .

$n^{3} + 2 n^{2} - 4 \cdot n$

$n^{3} + 2 n^{2} - 4 n$