Simplify (x^2-64)/(5x-1)

$\frac{x^{2} - 64}{5 x - 1}$

Rewrite $64$ as $8^{2}$ .

$\frac{x^{2} - 8^{2}}{5 x - 1}$

Since both terms are perfect squares, factor using the difference of squares formula, $a^{2} - b^{2} = (a + b) (a - b)$ where $a = x$ and $b = 8$ .

$\frac{(x + 8) (x - 8)}{5 x - 1}$