Solve by Graphing 2x+y=4 -4x-2y=-8

$2 x + y = 4$ $- 4 x - 2 y = - 8$

Step 1

Subtract $2 x$ from both sides of the equation.

$y = 4 - 2 x$

$- 4 x - 2 y = - 8$

Step 2

Add $4 x$ to both sides of the equation.

$- 2 y = - 8 + 4 x$

$y = 4 - 2 x$

Step 3

Divide each term in $- 2 y = - 8 + 4 x$ by $- 2$ and simplify.

Divide each term in $- 2 y = - 8 + 4 x$ by $- 2$ .

$\frac{- 2 y}{- 2} = \frac{- 8}{- 2} + \frac{4 x}{- 2}$

$y = 4 - 2 x$

Simplify the left side.

Cancel the common factor of $- 2$ .

Cancel the common factor.

$\frac{- 2 y}{- 2} = \frac{- 8}{- 2} + \frac{4 x}{- 2}$

$y = 4 - 2 x$

Divide $y$ by $1$ .

$y = \frac{- 8}{- 2} + \frac{4 x}{- 2}$

$y = 4 - 2 x$

$y = \frac{- 8}{- 2} + \frac{4 x}{- 2}$

$y = 4 - 2 x$

$y = \frac{- 8}{- 2} + \frac{4 x}{- 2}$

$y = 4 - 2 x$

Simplify the right side.

Simplify each term.

Divide $- 8$ by $- 2$ .

$y = 4 + \frac{4 x}{- 2}$

$y = 4 - 2 x$

Cancel the common factor of $4$ and $- 2$ .

Factor $2$ out of $4 x$ .

$y = 4 + \frac{2 (2 x)}{- 2}$

$y = 4 - 2 x$

Move the negative one from the denominator of $\frac{2 x}{- 1}$ .

$y = 4 - 1 \cdot (2 x)$

$y = 4 - 2 x$

$y = 4 - 1 \cdot (2 x)$

$y = 4 - 2 x$

Rewrite $- 1 \cdot (2 x)$ as $- (2 x)$ .

$y = 4 - (2 x)$

$y = 4 - 2 x$

Multiply $2$ by $- 1$ .

$y = 4 - 2 x$

Step 4

Create a graph to locate the intersection of the equations. The intersection of the system of equations is the solution.

$y = 4 - 2 x$

Step 5

Solve by Graphing 2x+y=4 -4x-2y=-8

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