Solve the Inequality for v 5(2v+3)-10v>-10

$5 (2 v + 3) - 10 v > - 10$

Step 1

Simplify $5 (2 v + 3) - 10 v$ .

Simplify each term.

Apply the distributive property.

$5 (2 v) + 5 \cdot 3 - 10 v > - 10$

Multiply $2$ by $5$ .

$10 v + 5 \cdot 3 - 10 v > - 10$

Multiply $5$ by $3$ .

$10 v + 15 - 10 v > - 10$

Combine the opposite terms in $10 v + 15 - 10 v$ .

Subtract $10 v$ from $10 v$ .

$0 + 15 > - 10$

Add $0$ and $15$ .

$15 > - 10$

Step 2

Since $15 > - 10$ , the inequality will always be true.

Always true

Step 3

The result can be shown in multiple forms.

Always true

Interval Notation:

$(- \infty, \infty)$