Solve the System of Equations -x+8y-z=4 x-10y-7z=-6 x+4y+9z=8

$- x + 8 y - z = 4$ $x - 10 y - 7 z = - 6$ $x + 4 y + 9 z = 8$

Step 1

Move all terms not containing $x$ to the right side of the equation.

Add $10 y$ to both sides of the equation.

$x - 7 z = - 6 + 10 y$

$- x + 8 y - z = 4$

$x + 4 y + 9 z = 8$

Add $7 z$ to both sides of the equation.

$x = - 6 + 10 y + 7 z$

$- x + 8 y - z = 4$

$x + 4 y + 9 z = 8$

$x = - 6 + 10 y + 7 z$

$- x + 8 y - z = 4$

$x + 4 y + 9 z = 8$

Step 2

Replace all occurrences of $x$ with $- 6 + 10 y + 7 z$ in each equation.

Replace all occurrences of $x$ in $- x + 8 y - z = 4$ with $- 6 + 10 y + 7 z$ .

$- (- 6 + 10 y + 7 z) + 8 y - z = 4$

$x = - 6 + 10 y + 7 z$

$x + 4 y + 9 z = 8$

Simplify the left side.

Simplify $- (- 6 + 10 y + 7 z) + 8 y - z$ .

Simplify each term.

Apply the distributive property.

$6 - (10 y) - (7 z) + 8 y - z = 4$

$x = - 6 + 10 y + 7 z$

$x + 4 y + 9 z = 8$

Simplify.

Multiply $- 1$ by $- 6$ .

$6 - (10 y) - (7 z) + 8 y - z = 4$

$x = - 6 + 10 y + 7 z$

$x + 4 y + 9 z = 8$

Multiply $10$ by $- 1$ .

$6 - 10 y - (7 z) + 8 y - z = 4$

$x = - 6 + 10 y + 7 z$

$x + 4 y + 9 z = 8$

Multiply $7$ by $- 1$ .

$6 - 10 y - 7 z + 8 y - z = 4$

$x = - 6 + 10 y + 7 z$

$x + 4 y + 9 z = 8$

$6 - 10 y - 7 z + 8 y - z = 4$

$x = - 6 + 10 y + 7 z$

$x + 4 y + 9 z = 8$

$6 - 10 y - 7 z + 8 y - z = 4$

$x = - 6 + 10 y + 7 z$

$x + 4 y + 9 z = 8$

Simplify by adding terms.

Add $- 10 y$ and $8 y$ .

$6 - 2 y - 7 z - z = 4$

$x = - 6 + 10 y + 7 z$

$x + 4 y + 9 z = 8$

Subtract $z$ from $- 7 z$ .

$6 - 2 y - 8 z = 4$

$x = - 6 + 10 y + 7 z$

$x + 4 y + 9 z = 8$

$6 - 2 y - 8 z = 4$

$x = - 6 + 10 y + 7 z$

$x + 4 y + 9 z = 8$

$6 - 2 y - 8 z = 4$

$x = - 6 + 10 y + 7 z$

$x + 4 y + 9 z = 8$

$6 - 2 y - 8 z = 4$

$x = - 6 + 10 y + 7 z$

$x + 4 y + 9 z = 8$

Replace all occurrences of $x$ in $x + 4 y + 9 z = 8$ with $- 6 + 10 y + 7 z$ .

$(- 6 + 10 y + 7 z) + 4 y + 9 z = 8$

$6 - 2 y - 8 z = 4$

$x = - 6 + 10 y + 7 z$

Simplify the left side.

Simplify $(- 6 + 10 y + 7 z) + 4 y + 9 z$ .

Add $10 y$ and $4 y$ .

$- 6 + 14 y + 7 z + 9 z = 8$

$6 - 2 y - 8 z = 4$

$x = - 6 + 10 y + 7 z$

Add $7 z$ and $9 z$ .

$- 6 + 14 y + 16 z = 8$

$6 - 2 y - 8 z = 4$

$x = - 6 + 10 y + 7 z$

$- 6 + 14 y + 16 z = 8$

$6 - 2 y - 8 z = 4$

$x = - 6 + 10 y + 7 z$

$- 6 + 14 y + 16 z = 8$

$6 - 2 y - 8 z = 4$

$x = - 6 + 10 y + 7 z$

$- 6 + 14 y + 16 z = 8$

$6 - 2 y - 8 z = 4$

$x = - 6 + 10 y + 7 z$

Step 3

Solve for $y$ in $- 6 + 14 y + 16 z = 8$ .

Move all terms not containing $y$ to the right side of the equation.

Add $6$ to both sides of the equation.

$14 y + 16 z = 8 + 6$

$6 - 2 y - 8 z = 4$

$x = - 6 + 10 y + 7 z$

Subtract $16 z$ from both sides of the equation.

$14 y = 8 + 6 - 16 z$

$6 - 2 y - 8 z = 4$

$x = - 6 + 10 y + 7 z$

Add $8$ and $6$ .

$14 y = 14 - 16 z$

$6 - 2 y - 8 z = 4$

$x = - 6 + 10 y + 7 z$

$14 y = 14 - 16 z$

$6 - 2 y - 8 z = 4$

$x = - 6 + 10 y + 7 z$

Divide each term in $14 y = 14 - 16 z$ by $14$ and simplify.

Divide each term in $14 y = 14 - 16 z$ by $14$ .

$\frac{14 y}{14} = \frac{14}{14} + \frac{- 16 z}{14}$

$6 - 2 y - 8 z = 4$

$x = - 6 + 10 y + 7 z$

Simplify the left side.

Cancel the common factor of $14$ .

Cancel the common factor.

$\frac{14 y}{14} = \frac{14}{14} + \frac{- 16 z}{14}$

$6 - 2 y - 8 z = 4$

$x = - 6 + 10 y + 7 z$

Divide $y$ by $1$ .

$y = \frac{14}{14} + \frac{- 16 z}{14}$

$6 - 2 y - 8 z = 4$

$x = - 6 + 10 y + 7 z$

$y = \frac{14}{14} + \frac{- 16 z}{14}$

$6 - 2 y - 8 z = 4$

$x = - 6 + 10 y + 7 z$

$y = \frac{14}{14} + \frac{- 16 z}{14}$

$6 - 2 y - 8 z = 4$

$x = - 6 + 10 y + 7 z$

Simplify the right side.

Simplify each term.

Divide $14$ by $14$ .

$y = 1 + \frac{- 16 z}{14}$

$6 - 2 y - 8 z = 4$

$x = - 6 + 10 y + 7 z$

Cancel the common factor of $- 16$ and $14$ .

Factor $2$ out of $- 16 z$ .

$y = 1 + \frac{2 (- 8 z)}{14}$

$6 - 2 y - 8 z = 4$

$x = - 6 + 10 y + 7 z$

Cancel the common factors.

Factor $2$ out of $14$ .

$y = 1 + \frac{2 (- 8 z)}{2 (7)}$

$6 - 2 y - 8 z = 4$

$x = - 6 + 10 y + 7 z$

Cancel the common factor.

$y = 1 + \frac{2 (- 8 z)}{2 \cdot 7}$

$6 - 2 y - 8 z = 4$

$x = - 6 + 10 y + 7 z$

Rewrite the expression.

$y = 1 + \frac{- 8 z}{7}$

$6 - 2 y - 8 z = 4$

$x = - 6 + 10 y + 7 z$

$y = 1 + \frac{- 8 z}{7}$

$6 - 2 y - 8 z = 4$

$x = - 6 + 10 y + 7 z$

$y = 1 + \frac{- 8 z}{7}$

$6 - 2 y - 8 z = 4$

$x = - 6 + 10 y + 7 z$

Move the negative in front of the fraction.

$y = 1 - \frac{8 z}{7}$

$6 - 2 y - 8 z = 4$

$x = - 6 + 10 y + 7 z$

$y = 1 - \frac{8 z}{7}$

$6 - 2 y - 8 z = 4$

$x = - 6 + 10 y + 7 z$

$y = 1 - \frac{8 z}{7}$

$6 - 2 y - 8 z = 4$

$x = - 6 + 10 y + 7 z$

$y = 1 - \frac{8 z}{7}$

$6 - 2 y - 8 z = 4$

$x = - 6 + 10 y + 7 z$

$y = 1 - \frac{8 z}{7}$

$6 - 2 y - 8 z = 4$

$x = - 6 + 10 y + 7 z$

Step 4

Replace all occurrences of $y$ with $1 - \frac{8 z}{7}$ in each equation.

Replace all occurrences of $y$ in $6 - 2 y - 8 z = 4$ with $1 - \frac{8 z}{7}$ .

$6 - 2 (1 - \frac{8 z}{7}) - 8 z = 4$

$y = 1 - \frac{8 z}{7}$

$x = - 6 + 10 y + 7 z$

Simplify the left side.

Simplify $6 - 2 (1 - \frac{8 z}{7}) - 8 z$ .

Simplify each term.

Apply the distributive property.

$6 - 2 \cdot 1 - 2 (- \frac{8 z}{7}) - 8 z = 4$

$y = 1 - \frac{8 z}{7}$

$x = - 6 + 10 y + 7 z$

Multiply $- 2$ by $1$ .

$6 - 2 - 2 (- \frac{8 z}{7}) - 8 z = 4$

$y = 1 - \frac{8 z}{7}$

$x = - 6 + 10 y + 7 z$

Multiply $- 2 (- \frac{8 z}{7})$ .

Multiply $- 1$ by $- 2$ .

$6 - 2 + 2 (\frac{8 z}{7}) - 8 z = 4$

$y = 1 - \frac{8 z}{7}$

$x = - 6 + 10 y + 7 z$

Combine $2$ and $\frac{8 z}{7}$ .

$6 - 2 + \frac{2 (8 z)}{7} - 8 z = 4$

$y = 1 - \frac{8 z}{7}$

$x = - 6 + 10 y + 7 z$

Multiply $8$ by $2$ .

$6 - 2 + \frac{16 z}{7} - 8 z = 4$

$y = 1 - \frac{8 z}{7}$

$x = - 6 + 10 y + 7 z$

$6 - 2 + \frac{16 z}{7} - 8 z = 4$

$y = 1 - \frac{8 z}{7}$

$x = - 6 + 10 y + 7 z$

$6 - 2 + \frac{16 z}{7} - 8 z = 4$

$y = 1 - \frac{8 z}{7}$

$x = - 6 + 10 y + 7 z$

Subtract $2$ from $6$ .

$4 + \frac{16 z}{7} - 8 z = 4$

$y = 1 - \frac{8 z}{7}$

$x = - 6 + 10 y + 7 z$

To write $- 8 z$ as a fraction with a common denominator, multiply by $\frac{7}{7}$ .

$4 + \frac{16 z}{7} - 8 z \cdot \frac{7}{7} = 4$

$y = 1 - \frac{8 z}{7}$

$x = - 6 + 10 y + 7 z$

Simplify terms.

Combine $- 8 z$ and $\frac{7}{7}$ .

$4 + \frac{16 z}{7} + \frac{- 8 z \cdot 7}{7} = 4$

$y = 1 - \frac{8 z}{7}$

$x = - 6 + 10 y + 7 z$

Combine the numerators over the common denominator.

$4 + \frac{16 z - 8 z \cdot 7}{7} = 4$

$y = 1 - \frac{8 z}{7}$

$x = - 6 + 10 y + 7 z$

$4 + \frac{16 z - 8 z \cdot 7}{7} = 4$

$y = 1 - \frac{8 z}{7}$

$x = - 6 + 10 y + 7 z$

Simplify each term.

Simplify the numerator.

Factor $8 z$ out of $16 z - 8 z \cdot 7$ .

Factor $8 z$ out of $16 z$ .

$4 + \frac{8 z (2) - 8 z \cdot 7}{7} = 4$

$y = 1 - \frac{8 z}{7}$

$x = - 6 + 10 y + 7 z$

Factor $8 z$ out of $- 8 z \cdot 7$ .

$4 + \frac{8 z (2) + 8 z (- 1 \cdot 7)}{7} = 4$

$y = 1 - \frac{8 z}{7}$

$x = - 6 + 10 y + 7 z$

Factor $8 z$ out of $8 z (2) + 8 z (- 1 \cdot 7)$ .

$4 + \frac{8 z (2 - 1 \cdot 7)}{7} = 4$

$y = 1 - \frac{8 z}{7}$

$x = - 6 + 10 y + 7 z$

$4 + \frac{8 z (2 - 1 \cdot 7)}{7} = 4$

$y = 1 - \frac{8 z}{7}$

$x = - 6 + 10 y + 7 z$

Multiply $- 1$ by $7$ .

$4 + \frac{8 z (2 - 7)}{7} = 4$

$y = 1 - \frac{8 z}{7}$

$x = - 6 + 10 y + 7 z$

Subtract $7$ from $2$ .

$4 + \frac{8 z \cdot - 5}{7} = 4$

$y = 1 - \frac{8 z}{7}$

$x = - 6 + 10 y + 7 z$

Multiply $- 5$ by $8$ .

$4 + \frac{- 40 z}{7} = 4$

$y = 1 - \frac{8 z}{7}$

$x = - 6 + 10 y + 7 z$

$4 + \frac{- 40 z}{7} = 4$

$y = 1 - \frac{8 z}{7}$

$x = - 6 + 10 y + 7 z$

Move the negative in front of the fraction.

$4 - \frac{40 z}{7} = 4$

$y = 1 - \frac{8 z}{7}$

$x = - 6 + 10 y + 7 z$

$4 - \frac{40 z}{7} = 4$

$y = 1 - \frac{8 z}{7}$

$x = - 6 + 10 y + 7 z$

$4 - \frac{40 z}{7} = 4$

$y = 1 - \frac{8 z}{7}$

$x = - 6 + 10 y + 7 z$

$4 - \frac{40 z}{7} = 4$

$y = 1 - \frac{8 z}{7}$

$x = - 6 + 10 y + 7 z$

Replace all occurrences of $y$ in $x = - 6 + 10 y + 7 z$ with $1 - \frac{8 z}{7}$ .

$x = - 6 + 10 (1 - \frac{8 z}{7}) + 7 z$

$4 - \frac{40 z}{7} = 4$

$y = 1 - \frac{8 z}{7}$

Simplify the right side.

Simplify $- 6 + 10 (1 - \frac{8 z}{7}) + 7 z$ .

Simplify each term.

Apply the distributive property.

$x = - 6 + 10 \cdot 1 + 10 (- \frac{8 z}{7}) + 7 z$

$4 - \frac{40 z}{7} = 4$

$y = 1 - \frac{8 z}{7}$

Multiply $10$ by $1$ .

$x = - 6 + 10 + 10 (- \frac{8 z}{7}) + 7 z$

$4 - \frac{40 z}{7} = 4$

$y = 1 - \frac{8 z}{7}$

Multiply $10 (- \frac{8 z}{7})$ .

Multiply $- 1$ by $10$ .

$x = - 6 + 10 - 10 \frac{8 z}{7} + 7 z$

$4 - \frac{40 z}{7} = 4$

$y = 1 - \frac{8 z}{7}$

Combine $- 10$ and $\frac{8 z}{7}$ .

$x = - 6 + 10 + \frac{- 10 (8 z)}{7} + 7 z$

$4 - \frac{40 z}{7} = 4$

$y = 1 - \frac{8 z}{7}$

Multiply $8$ by $- 10$ .

$x = - 6 + 10 + \frac{- 80 z}{7} + 7 z$

$4 - \frac{40 z}{7} = 4$

$y = 1 - \frac{8 z}{7}$

$x = - 6 + 10 + \frac{- 80 z}{7} + 7 z$

$4 - \frac{40 z}{7} = 4$

$y = 1 - \frac{8 z}{7}$

Move the negative in front of the fraction.

$x = - 6 + 10 - \frac{80 z}{7} + 7 z$

$4 - \frac{40 z}{7} = 4$

$y = 1 - \frac{8 z}{7}$

$x = - 6 + 10 - \frac{80 z}{7} + 7 z$

$4 - \frac{40 z}{7} = 4$

$y = 1 - \frac{8 z}{7}$

Add $- 6$ and $10$ .

$x = 4 - \frac{80 z}{7} + 7 z$

$4 - \frac{40 z}{7} = 4$

$y = 1 - \frac{8 z}{7}$

To write $7 z$ as a fraction with a common denominator, multiply by $\frac{7}{7}$ .

$x = 4 - \frac{80 z}{7} + 7 z \cdot \frac{7}{7}$

$4 - \frac{40 z}{7} = 4$

$y = 1 - \frac{8 z}{7}$

Simplify terms.

Combine $7 z$ and $\frac{7}{7}$ .

$x = 4 - \frac{80 z}{7} + \frac{7 z \cdot 7}{7}$

$4 - \frac{40 z}{7} = 4$

$y = 1 - \frac{8 z}{7}$

Combine the numerators over the common denominator.

$x = 4 + \frac{- 80 z + 7 z \cdot 7}{7}$

$4 - \frac{40 z}{7} = 4$

$y = 1 - \frac{8 z}{7}$

$x = 4 + \frac{- 80 z + 7 z \cdot 7}{7}$

$4 - \frac{40 z}{7} = 4$

$y = 1 - \frac{8 z}{7}$

Simplify each term.

Simplify the numerator.

Factor $z$ out of $- 80 z + 7 z \cdot 7$ .

Factor $z$ out of $- 80 z$ .

$x = 4 + \frac{z \cdot - 80 + 7 z \cdot 7}{7}$

$4 - \frac{40 z}{7} = 4$

$y = 1 - \frac{8 z}{7}$

Factor $z$ out of $7 z \cdot 7$ .

$x = 4 + \frac{z \cdot - 80 + z (7 \cdot 7)}{7}$

$4 - \frac{40 z}{7} = 4$

$y = 1 - \frac{8 z}{7}$

Factor $z$ out of $z \cdot - 80 + z (7 \cdot 7)$ .

$x = 4 + \frac{z (- 80 + 7 \cdot 7)}{7}$

$4 - \frac{40 z}{7} = 4$

$y = 1 - \frac{8 z}{7}$

$x = 4 + \frac{z (- 80 + 7 \cdot 7)}{7}$

$4 - \frac{40 z}{7} = 4$

$y = 1 - \frac{8 z}{7}$

Multiply $7$ by $7$ .

$x = 4 + \frac{z (- 80 + 49)}{7}$

$4 - \frac{40 z}{7} = 4$

$y = 1 - \frac{8 z}{7}$

Add $- 80$ and $49$ .

$x = 4 + \frac{z \cdot - 31}{7}$

$4 - \frac{40 z}{7} = 4$

$y = 1 - \frac{8 z}{7}$

$x = 4 + \frac{z \cdot - 31}{7}$

$4 - \frac{40 z}{7} = 4$

$y = 1 - \frac{8 z}{7}$

Move $- 31$ to the left of $z$ .

$x = 4 + \frac{- 31 \cdot z}{7}$

$4 - \frac{40 z}{7} = 4$

$y = 1 - \frac{8 z}{7}$

Move the negative in front of the fraction.

$x = 4 - \frac{31 z}{7}$

$4 - \frac{40 z}{7} = 4$

$y = 1 - \frac{8 z}{7}$

$x = 4 - \frac{31 z}{7}$

$4 - \frac{40 z}{7} = 4$

$y = 1 - \frac{8 z}{7}$

$x = 4 - \frac{31 z}{7}$

$4 - \frac{40 z}{7} = 4$

$y = 1 - \frac{8 z}{7}$

$x = 4 - \frac{31 z}{7}$

$4 - \frac{40 z}{7} = 4$

$y = 1 - \frac{8 z}{7}$

$x = 4 - \frac{31 z}{7}$

$4 - \frac{40 z}{7} = 4$

$y = 1 - \frac{8 z}{7}$

Step 5

Solve for $z$ in $4 - \frac{40 z}{7} = 4$ .

Move all terms not containing $z$ to the right side of the equation.

Subtract $4$ from both sides of the equation.

$- \frac{40 z}{7} = 4 - 4$

$x = 4 - \frac{31 z}{7}$

$y = 1 - \frac{8 z}{7}$

Subtract $4$ from $4$ .

$- \frac{40 z}{7} = 0$

$x = 4 - \frac{31 z}{7}$

$y = 1 - \frac{8 z}{7}$

$- \frac{40 z}{7} = 0$

$x = 4 - \frac{31 z}{7}$

$y = 1 - \frac{8 z}{7}$

Set the numerator equal to zero.

$40 z = 0$

$x = 4 - \frac{31 z}{7}$

$y = 1 - \frac{8 z}{7}$

Divide each term in $40 z = 0$ by $40$ and simplify.

Divide each term in $40 z = 0$ by $40$ .

$\frac{40 z}{40} = \frac{0}{40}$

$x = 4 - \frac{31 z}{7}$

$y = 1 - \frac{8 z}{7}$

Simplify the left side.

Cancel the common factor of $40$ .

Cancel the common factor.

$\frac{40 z}{40} = \frac{0}{40}$

$x = 4 - \frac{31 z}{7}$

$y = 1 - \frac{8 z}{7}$

Divide $z$ by $1$ .

$z = \frac{0}{40}$

$x = 4 - \frac{31 z}{7}$

$y = 1 - \frac{8 z}{7}$

$z = \frac{0}{40}$

$x = 4 - \frac{31 z}{7}$

$y = 1 - \frac{8 z}{7}$

$z = \frac{0}{40}$

$x = 4 - \frac{31 z}{7}$

$y = 1 - \frac{8 z}{7}$

Simplify the right side.

Divide $0$ by $40$ .

$z = 0$

$x = 4 - \frac{31 z}{7}$

$y = 1 - \frac{8 z}{7}$

$z = 0$

$x = 4 - \frac{31 z}{7}$

$y = 1 - \frac{8 z}{7}$

$z = 0$

$x = 4 - \frac{31 z}{7}$

$y = 1 - \frac{8 z}{7}$

$z = 0$

$x = 4 - \frac{31 z}{7}$

$y = 1 - \frac{8 z}{7}$

Step 6

Replace all occurrences of $z$ with $0$ in each equation.

Replace all occurrences of $z$ in $x = 4 - \frac{31 z}{7}$ with $0$ .

$x = 4 - \frac{31 (0)}{7}$

$z = 0$

$y = 1 - \frac{8 z}{7}$

Simplify the right side.

Simplify $4 - \frac{31 (0)}{7}$ .

Simplify each term.

Cancel the common factor of $0$ and $7$ .

Factor $7$ out of $31 (0)$ .

$x = 4 - \frac{7 (31 \cdot (0))}{7}$

$z = 0$

$y = 1 - \frac{8 z}{7}$

Cancel the common factors.

Factor $7$ out of $7$ .

$x = 4 - \frac{7 (31 \cdot (0))}{7 (1)}$

$z = 0$

$y = 1 - \frac{8 z}{7}$

Cancel the common factor.

$x = 4 - \frac{7 (31 \cdot (0))}{7 \cdot 1}$

$z = 0$

$y = 1 - \frac{8 z}{7}$

Rewrite the expression.

$x = 4 - \frac{31 \cdot (0)}{1}$

$z = 0$

$y = 1 - \frac{8 z}{7}$

Divide $31 \cdot (0)$ by $1$ .

$x = 4 - (31 \cdot (0))$

$z = 0$

$y = 1 - \frac{8 z}{7}$

$x = 4 - (31 \cdot (0))$

$z = 0$

$y = 1 - \frac{8 z}{7}$

$x = 4 - (31 \cdot (0))$

$z = 0$

$y = 1 - \frac{8 z}{7}$

Multiply $- (31 \cdot (0))$ .

Multiply $31$ by $0$ .

$x = 4 - 0$

$z = 0$

$y = 1 - \frac{8 z}{7}$

Multiply $- 1$ by $0$ .

$x = 4 + 0$

$z = 0$

$y = 1 - \frac{8 z}{7}$

$x = 4 + 0$

$z = 0$

$y = 1 - \frac{8 z}{7}$

$x = 4 + 0$

$z = 0$

$y = 1 - \frac{8 z}{7}$

Add $4$ and $0$ .

$x = 4$

$z = 0$

$y = 1 - \frac{8 z}{7}$

$x = 4$

$z = 0$

$y = 1 - \frac{8 z}{7}$

$x = 4$

$z = 0$

$y = 1 - \frac{8 z}{7}$

Replace all occurrences of $z$ in $y = 1 - \frac{8 z}{7}$ with $0$ .

$y = 1 - \frac{8 (0)}{7}$

$x = 4$

$z = 0$

Simplify the right side.

Simplify $1 - \frac{8 (0)}{7}$ .

Simplify each term.

Cancel the common factor of $0$ and $7$ .

Factor $7$ out of $8 (0)$ .

$y = 1 - \frac{7 (8 \cdot (0))}{7}$

$x = 4$

$z = 0$

Cancel the common factors.

Factor $7$ out of $7$ .

$y = 1 - \frac{7 (8 \cdot (0))}{7 (1)}$

$x = 4$

$z = 0$

Cancel the common factor.

$y = 1 - \frac{7 (8 \cdot (0))}{7 \cdot 1}$

$x = 4$

$z = 0$

Rewrite the expression.

$y = 1 - \frac{8 \cdot (0)}{1}$

$x = 4$

$z = 0$

Divide $8 \cdot (0)$ by $1$ .

$y = 1 - (8 \cdot (0))$

$x = 4$

$z = 0$

$y = 1 - (8 \cdot (0))$

$x = 4$

$z = 0$

$y = 1 - (8 \cdot (0))$

$x = 4$

$z = 0$

Multiply $- (8 \cdot (0))$ .

Multiply $8$ by $0$ .

$y = 1 - 0$

$x = 4$

$z = 0$

Multiply $- 1$ by $0$ .

$y = 1 + 0$

$x = 4$

$z = 0$

$y = 1 + 0$

$x = 4$

$z = 0$

$y = 1 + 0$

$x = 4$

$z = 0$

Add $1$ and $0$ .

$y = 1$

$x = 4$

$z = 0$

$y = 1$

$x = 4$

$z = 0$

$y = 1$

$x = 4$

$z = 0$

$y = 1$

$x = 4$

$z = 0$

Step 7

The solution to the system is the complete set of ordered pairs that are valid solutions.

$(4, 1, 0)$

Step 8

The result can be shown in multiple forms.

Point Form:

$(4, 1, 0)$

Equation Form:

$x = 4, y = 1, z = 0$

Solve the System of Equations -x+8y-z=4 x-10y-7z=-6 x+4y+9z=8

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