Find the Perpendicular Line (-6,4) , 3y=2x-3

$(- 6, 4)$ , $3 y = 2 x - 3$

Step 1

Divide each term in $3 y = 2 x - 3$ by $3$ and simplify.

Divide each term in $3 y = 2 x - 3$ by $3$ .

$\frac{3 y}{3} = \frac{2 x}{3} + \frac{- 3}{3}$

Simplify the left side.

Cancel the common factor of $3$ .

Cancel the common factor.

$\frac{3 y}{3} = \frac{2 x}{3} + \frac{- 3}{3}$

Divide $y$ by $1$ .

$y = \frac{2 x}{3} + \frac{- 3}{3}$

Simplify the right side.

Divide $- 3$ by $3$ .

$y = \frac{2 x}{3} - 1$

Step 2

Find the slope when $y = \frac{2 x}{3} - 1$ .

Rewrite in slope-intercept form.

The slope-intercept form is $y = m x + b$ , where $m$ is the slope and $b$ is the y-intercept.

$y = m x + b$

Reorder terms.

$y = \frac{2}{3} x - 1$

Using the slope-intercept form, the slope is $\frac{2}{3}$ .

$m = \frac{2}{3}$

Step 3

The equation of a perpendicular line must have a slope that is the negative reciprocal of the original slope.

$m_{perpendicular} = - \frac{1}{\frac{2}{3}}$

Step 4

Simplify $- \frac{1}{\frac{2}{3}}$ to find the slope of the perpendicular line.

Multiply the numerator by the reciprocal of the denominator.

$m_{perpendicular} = - (1 (\frac{3}{2}))$

Multiply $\frac{3}{2}$ by $1$ .

$m_{perpendicular} = - \frac{3}{2}$

Step 5

Find the equation of the perpendicular line using the point-slope formula.

Use the slope $- \frac{3}{2}$ and a given point $(- 6, 4)$ to substitute for $x_{1}$ and $y_{1}$ in the point-slope form $y - y_{1} = m (x - x_{1})$ , which is derived from the slope equation $m = \frac{y_{2} - y_{1}}{x_{2} - x_{1}}$ .

$y - (4) = - \frac{3}{2} \cdot (x - (- 6))$

Simplify the equation and keep it in point-slope form.

$y - 4 = - \frac{3}{2} \cdot (x + 6)$

Step 6

Write in $y = m x + b$ form.

Solve for $y$ .

Simplify $- \frac{3}{2} \cdot (x + 6)$ .

Rewrite.

$y - 4 = 0 + 0 - \frac{3}{2} \cdot (x + 6)$

Simplify terms.

Apply the distributive property.

$y - 4 = - \frac{3}{2} x - \frac{3}{2} \cdot 6$

Combine $x$ and $\frac{3}{2}$ .

$y - 4 = - \frac{x \cdot 3}{2} - \frac{3}{2} \cdot 6$

Cancel the common factor of $2$ .

Move the leading negative in $- \frac{3}{2}$ into the numerator.

$y - 4 = - \frac{x \cdot 3}{2} + \frac{- 3}{2} \cdot 6$

Factor $2$ out of $6$ .

$y - 4 = - \frac{x \cdot 3}{2} + \frac{- 3}{2} \cdot (2 (3))$

Cancel the common factor.

$y - 4 = - \frac{x \cdot 3}{2} + \frac{- 3}{2} \cdot (2 \cdot 3)$

Rewrite the expression.

$y - 4 = - \frac{x \cdot 3}{2} - 3 \cdot 3$

Multiply $- 3$ by $3$ .

$y - 4 = - \frac{x \cdot 3}{2} - 9$

Move $3$ to the left of $x$ .

$y - 4 = - \frac{3 x}{2} - 9$

Move all terms not containing $y$ to the right side of the equation.

Add $4$ to both sides of the equation.

$y = - \frac{3 x}{2} - 9 + 4$

Add $- 9$ and $4$ .

$y = - \frac{3 x}{2} - 5$

Reorder terms.

$y = - (\frac{3}{2} x) - 5$

Remove parentheses.

$y = - \frac{3}{2} x - 5$

Step 7

Find the Perpendicular Line (-6,4) , 3y=2x-3

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