Simplify (4x^2+2x)/((x^2+x-2)/((8x^2+4x)/(3x^2+10x+8)))

$\frac{4 x^{2} + 2 x}{\frac{x^{2} + x - 2}{\frac{8 x^{2} + 4 x}{3 x^{2} + 10 x + 8}}}$

Step 1

Multiply the numerator by the reciprocal of the denominator.

$(4 x^{2} + 2 x) \frac{\frac{8 x^{2} + 4 x}{3 x^{2} + 10 x + 8}}{x^{2} + x - 2}$

Step 2

Factor $4 x$ out of $8 x^{2} + 4 x$ .

Factor $4 x$ out of $8 x^{2}$ .

$(4 x^{2} + 2 x) \frac{\frac{4 x (2 x) + 4 x}{3 x^{2} + 10 x + 8}}{x^{2} + x - 2}$

Factor $4 x$ out of $4 x$ .

$(4 x^{2} + 2 x) \frac{\frac{4 x (2 x) + 4 x (1)}{3 x^{2} + 10 x + 8}}{x^{2} + x - 2}$

Factor $4 x$ out of $4 x (2 x) + 4 x (1)$ .

$(4 x^{2} + 2 x) \frac{\frac{4 x (2 x + 1)}{3 x^{2} + 10 x + 8}}{x^{2} + x - 2}$

Step 3

Factor by grouping.

For a polynomial of the form $a x^{2} + b x + c$ , rewrite the middle term as a sum of two terms whose product is $a \cdot c = 3 \cdot 8 = 24$ and whose sum is $b = 10$ .

Factor $10$ out of $10 x$ .

$(4 x^{2} + 2 x) \frac{\frac{4 x (2 x + 1)}{3 x^{2} + 10 (x) + 8}}{x^{2} + x - 2}$

Rewrite $10$ as $4$ plus $6$

$(4 x^{2} + 2 x) \frac{\frac{4 x (2 x + 1)}{3 x^{2} + (4 + 6) x + 8}}{x^{2} + x - 2}$

Apply the distributive property.

$(4 x^{2} + 2 x) \frac{\frac{4 x (2 x + 1)}{3 x^{2} + 4 x + 6 x + 8}}{x^{2} + x - 2}$

Factor out the greatest common factor from each group.

Group the first two terms and the last two terms.

$(4 x^{2} + 2 x) \frac{\frac{4 x (2 x + 1)}{(3 x^{2} + 4 x) + 6 x + 8}}{x^{2} + x - 2}$

Factor out the greatest common factor (GCF) from each group.

$(4 x^{2} + 2 x) \frac{\frac{4 x (2 x + 1)}{x (3 x + 4) + 2 (3 x + 4)}}{x^{2} + x - 2}$

Factor the polynomial by factoring out the greatest common factor, $3 x + 4$ .

$(4 x^{2} + 2 x) \frac{\frac{4 x (2 x + 1)}{(3 x + 4) (x + 2)}}{x^{2} + x - 2}$

Step 4

Factor $x^{2} + x - 2$ using the AC method.

Consider the form $x^{2} + b x + c$ . Find a pair of integers whose product is $c$ and whose sum is $b$ . In this case, whose product is $- 2$ and whose sum is $1$ .

$- 1, 2$

Write the factored form using these integers.

$(4 x^{2} + 2 x) \frac{\frac{4 x (2 x + 1)}{(3 x + 4) (x + 2)}}{(x - 1) (x + 2)}$

Step 5

Multiply the numerator by the reciprocal of the denominator.

$(4 x^{2} + 2 x) (\frac{4 x (2 x + 1)}{(3 x + 4) (x + 2)} \cdot \frac{1}{(x - 1) (x + 2)})$

Step 6

Multiply $\frac{4 x (2 x + 1)}{(3 x + 4) (x + 2)} \cdot \frac{1}{(x - 1) (x + 2)}$ .

Multiply $\frac{4 x (2 x + 1)}{(3 x + 4) (x + 2)}$ by $\frac{1}{(x - 1) (x + 2)}$ .

$(4 x^{2} + 2 x) \frac{4 x (2 x + 1)}{(3 x + 4) (x + 2) ((x - 1) (x + 2))}$

Raise $x + 2$ to the power of $1$ .

$(4 x^{2} + 2 x) \frac{4 x (2 x + 1)}{(3 x + 4) ({(x + 2)}^{1} (x + 2)) (x - 1)}$

Raise $x + 2$ to the power of $1$ .

$(4 x^{2} + 2 x) \frac{4 x (2 x + 1)}{(3 x + 4) ({(x + 2)}^{1} {(x + 2)}^{1}) (x - 1)}$

Use the power rule $a^{m} a^{n} = a^{m + n}$ to combine exponents.

$(4 x^{2} + 2 x) \frac{4 x (2 x + 1)}{(3 x + 4) {(x + 2)}^{1 + 1} (x - 1)}$

Add $1$ and $1$ .

$(4 x^{2} + 2 x) \frac{4 x (2 x + 1)}{(3 x + 4) {(x + 2)}^{2} (x - 1)}$

Step 7

Multiply $4 x^{2} + 2 x$ by $\frac{4 x (2 x + 1)}{(3 x + 4) {(x + 2)}^{2} (x - 1)}$ .

$\frac{(4 x^{2} + 2 x) (4 x (2 x + 1))}{(3 x + 4) {(x + 2)}^{2} (x - 1)}$

Step 8

Simplify the numerator.

Factor $2 x$ out of $4 x^{2} + 2 x$ .

Factor $2 x$ out of $4 x^{2}$ .

$\frac{(2 x (2 x) + 2 x) \cdot 4 x (2 x + 1)}{(3 x + 4) {(x + 2)}^{2} (x - 1)}$

Factor $2 x$ out of $2 x$ .

$\frac{(2 x (2 x) + 2 x (1)) \cdot 4 x (2 x + 1)}{(3 x + 4) {(x + 2)}^{2} (x - 1)}$

Factor $2 x$ out of $2 x (2 x) + 2 x (1)$ .

$\frac{2 x (2 x + 1) \cdot 4 x (2 x + 1)}{(3 x + 4) {(x + 2)}^{2} (x - 1)}$

Combine exponents.

Multiply $4$ by $2$ .

$\frac{8 x (2 x + 1) x (2 x + 1)}{(3 x + 4) {(x + 2)}^{2} (x - 1)}$

Raise $x$ to the power of $1$ .

$\frac{8 (x^{1} x) (2 x + 1) (2 x + 1)}{(3 x + 4) {(x + 2)}^{2} (x - 1)}$

Raise $x$ to the power of $1$ .

$\frac{8 (x^{1} x^{1}) (2 x + 1) (2 x + 1)}{(3 x + 4) {(x + 2)}^{2} (x - 1)}$

Use the power rule $a^{m} a^{n} = a^{m + n}$ to combine exponents.

$\frac{8 x^{1 + 1} (2 x + 1) (2 x + 1)}{(3 x + 4) {(x + 2)}^{2} (x - 1)}$

Add $1$ and $1$ .

$\frac{8 x^{2} (2 x + 1) (2 x + 1)}{(3 x + 4) {(x + 2)}^{2} (x - 1)}$

Raise $2 x + 1$ to the power of $1$ .

$\frac{8 x^{2} ({(2 x + 1)}^{1} (2 x + 1))}{(3 x + 4) {(x + 2)}^{2} (x - 1)}$

Raise $2 x + 1$ to the power of $1$ .

$\frac{8 x^{2} ({(2 x + 1)}^{1} {(2 x + 1)}^{1})}{(3 x + 4) {(x + 2)}^{2} (x - 1)}$

Use the power rule $a^{m} a^{n} = a^{m + n}$ to combine exponents.

$\frac{8 x^{2} {(2 x + 1)}^{1 + 1}}{(3 x + 4) {(x + 2)}^{2} (x - 1)}$

Add $1$ and $1$ .

$\frac{8 x^{2} {(2 x + 1)}^{2}}{(3 x + 4) {(x + 2)}^{2} (x - 1)}$

Simplify (4x^2+2x)/((x^2+x-2)/((8x^2+4x)/(3x^2+10x+8)))

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