Convert to Interval Notation -13<=3+8p<=11

$- 13 \leq 3 + 8 p \leq 11$

Move all terms not containing $p$ from the center section of the inequality.

Subtract $3$ from each section of the inequality because it does not contain the variable we are trying to solve for.

$- 13 - 3 \leq 8 p \leq 11 - 3$

Subtract $3$ from $- 13$ .

$- 16 \leq 8 p \leq 11 - 3$

Subtract $3$ from $11$ .

$- 16 \leq 8 p \leq 8$

Divide each term in the inequality by $8$ .

$\frac{- 16}{8} \leq \frac{8 p}{8} \leq \frac{8}{8}$

Divide $- 16$ by $8$ .

$- 2 \leq \frac{8 p}{8} \leq \frac{8}{8}$

Cancel the common factor of $8$ .

Cancel the common factor.

$- 2 \leq \frac{8 p}{8} \leq \frac{8}{8}$

Divide $p$ by $1$ .

$- 2 \leq p \leq \frac{8}{8}$

Divide $8$ by $8$ .

$- 2 \leq p \leq 1$

Convert the inequality to interval notation.

$[- 2, 1]$