Convert to Interval Notation 4x+15>=x+6

$4 x + 15 \geq x + 6$

Step 1

Move all terms containing $x$ to the left side of the inequality.

Subtract $x$ from both sides of the inequality.

$4 x + 15 - x \geq 6$

Subtract $x$ from $4 x$ .

$3 x + 15 \geq 6$

Step 2

Move all terms not containing $x$ to the right side of the inequality.

Subtract $15$ from both sides of the inequality.

$3 x \geq 6 - 15$

Subtract $15$ from $6$ .

$3 x \geq - 9$

Step 3

Divide each term in $3 x \geq - 9$ by $3$ and simplify.

Divide each term in $3 x \geq - 9$ by $3$ .

$\frac{3 x}{3} \geq \frac{- 9}{3}$

Simplify the left side.

Cancel the common factor of $3$ .

Cancel the common factor.

$\frac{3 x}{3} \geq \frac{- 9}{3}$

Divide $x$ by $1$ .

$x \geq \frac{- 9}{3}$

Simplify the right side.

Divide $- 9$ by $3$ .

$x \geq - 3$

Step 4

Convert the inequality to interval notation.

$[- 3, \infty)$

Step 5