Convert to Interval Notation x^2+5x>=-4

$x^{2} + 5 x \geq - 4$

Step 1

Convert the inequality to an equation.

$x^{2} + 5 x = - 4$

Step 2

Add $4$ to both sides of the equation.

$x^{2} + 5 x + 4 = 0$

Step 3

Factor $x^{2} + 5 x + 4$ using the AC method.

Consider the form $x^{2} + b x + c$ . Find a pair of integers whose product is $c$ and whose sum is $b$ . In this case, whose product is $4$ and whose sum is $5$ .

$1, 4$

Write the factored form using these integers.

$(x + 1) (x + 4) = 0$

Step 4

If any individual factor on the left side of the equation is equal to $0$ , the entire expression will be equal to $0$ .

$x + 1 = 0$

$x + 4 = 0$

Step 5

Set $x + 1$ equal to $0$ and solve for $x$ .

Set $x + 1$ equal to $0$ .

$x + 1 = 0$

Subtract $1$ from both sides of the equation.

$x = - 1$

Step 6

Set $x + 4$ equal to $0$ and solve for $x$ .

Set $x + 4$ equal to $0$ .

$x + 4 = 0$

Subtract $4$ from both sides of the equation.

$x = - 4$

Step 7

The final solution is all the values that make $(x + 1) (x + 4) = 0$ true.

$x = - 1, - 4$

Step 8

Use each root to create test intervals.

$x < - 4$

$- 4 < x < - 1$

$x > - 1$

Step 9

Choose a test value from each interval and plug this value into the original inequality to determine which intervals satisfy the inequality.

Test a value on the interval $x < - 4$ to see if it makes the inequality true.

Choose a value on the interval $x < - 4$ and see if this value makes the original inequality true.

$x = - 6$

Replace $x$ with $- 6$ in the original inequality.

${(- 6)}^{2} + 5 (- 6) \geq - 4$

The left side $6$ is greater than the right side $- 4$ , which means that the given statement is always true.

True

Test a value on the interval $- 4 < x < - 1$ to see if it makes the inequality true.

Choose a value on the interval $- 4 < x < - 1$ and see if this value makes the original inequality true.

$x = - 2$

Replace $x$ with $- 2$ in the original inequality.

${(- 2)}^{2} + 5 (- 2) \geq - 4$

The left side $- 6$ is less than the right side $- 4$ , which means that the given statement is false.

False

Test a value on the interval $x > - 1$ to see if it makes the inequality true.

Choose a value on the interval $x > - 1$ and see if this value makes the original inequality true.

$x = 0$

Replace $x$ with $0$ in the original inequality.

${(0)}^{2} + 5 (0) \geq - 4$

The left side $0$ is greater than the right side $- 4$ , which means that the given statement is always true.

True

Compare the intervals to determine which ones satisfy the original inequality.

$x < - 4$ True

$- 4 < x < - 1$ False

$x > - 1$ True

$x < - 4$ True

$- 4 < x < - 1$ False

$x > - 1$ True

Step 10

The solution consists of all of the true intervals.

$x \leq - 4$ or $x \geq - 1$

Step 11

Convert the inequality to interval notation.

$(- \infty, - 4] \cup [- 1, \infty)$

Step 12

Convert to Interval Notation x^2+5x>=-4

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