Convert to Radical Form 1/((x-3)^(-1/2))

$\frac{1}{{(x - 3)}^{- \frac{1}{2}}}$

Move ${(x - 3)}^{- \frac{1}{2}}$ to the numerator using the negative exponent rule $\frac{1}{b^{- n}} = b^{n}$ .

${(x - 3)}^{\frac{1}{2}}$

Apply the rule $x^{\frac{m}{n}} = \sqrt[n]{x^{m}}$ to rewrite the exponentiation as a radical.

$\sqrt{{(x - 3)}^{1}}$

Anything raised to $1$ is the base itself.

$\sqrt{x - 3}$