Convert to Radical Form (2x^2-6)^(1/2)

${(2 x^{2} - 6)}^{\frac{1}{2}}$

Step 1

Apply the rule $x^{\frac{m}{n}} = \sqrt[n]{x^{m}}$ to rewrite the exponentiation as a radical.

$\sqrt{{(2 x^{2} - 6)}^{1}}$

Step 2

Anything raised to $1$ is the base itself.

$\sqrt{2 x^{2} - 6}$