Convert to Radical Form (3x^3)^(-2/7)

${(3 x^{3})}^{- \frac{2}{7}}$

Step 1

Rewrite the expression using the negative exponent rule $b^{- n} = \frac{1}{b^{n}}$ .

$\frac{1}{{(3 x^{3})}^{\frac{2}{7}}}$

Step 2

Apply the rule $x^{\frac{m}{n}} = \sqrt[n]{x^{m}}$ to rewrite the exponentiation as a radical.

$\frac{1}{\sqrt[7]{{(3 x^{3})}^{2}}}$