Convert to Radical Form (a^2b^2)^(1/9)

${(a^{2} b^{2})}^{\frac{1}{9}}$

Step 1

Apply the rule $x^{\frac{m}{n}} = \sqrt[n]{x^{m}}$ to rewrite the exponentiation as a radical.

$\sqrt[9]{{(a^{2} b^{2})}^{1}}$

Step 2

Anything raised to $1$ is the base itself.

$\sqrt[9]{a^{2} b^{2}}$