Convert to Radical Form (s/(r^2))^(-3/4)

${(\frac{s}{r^{2}})}^{- \frac{3}{4}}$

Step 1

Change the sign of the exponent by rewriting the base as its reciprocal.

${(\frac{r^{2}}{s})}^{\frac{3}{4}}$

Step 2

Apply the rule $x^{\frac{m}{n}} = \sqrt[n]{x^{m}}$ to rewrite the exponentiation as a radical.

$\sqrt[4]{{(\frac{r^{2}}{s})}^{3}}$