Determine if Linear 2y=6x^2-x+3

$2 y = 6 x^{2} - x + 3$

Step 1

Divide each term in $2 y = 6 x^{2} - x + 3$ by $2$ and simplify.

Divide each term in $2 y = 6 x^{2} - x + 3$ by $2$ .

$\frac{2 y}{2} = \frac{6 x^{2}}{2} + \frac{- x}{2} + \frac{3}{2}$

Simplify the left side.

Cancel the common factor of $2$ .

Cancel the common factor.

$\frac{2 y}{2} = \frac{6 x^{2}}{2} + \frac{- x}{2} + \frac{3}{2}$

Divide $y$ by $1$ .

$y = \frac{6 x^{2}}{2} + \frac{- x}{2} + \frac{3}{2}$

Simplify the right side.

Simplify each term.

Cancel the common factor of $6$ and $2$ .

Factor $2$ out of $6 x^{2}$ .

$y = \frac{2 (3 x^{2})}{2} + \frac{- x}{2} + \frac{3}{2}$

Cancel the common factors.

Factor $2$ out of $2$ .

$y = \frac{2 (3 x^{2})}{2 (1)} + \frac{- x}{2} + \frac{3}{2}$

Cancel the common factor.

$y = \frac{2 (3 x^{2})}{2 \cdot 1} + \frac{- x}{2} + \frac{3}{2}$

Rewrite the expression.

$y = \frac{3 x^{2}}{1} + \frac{- x}{2} + \frac{3}{2}$

Divide $3 x^{2}$ by $1$ .

$y = 3 x^{2} + \frac{- x}{2} + \frac{3}{2}$

Move the negative in front of the fraction.

$y = 3 x^{2} - \frac{x}{2} + \frac{3}{2}$

Step 2

A linear equation is an equation of a straight line, which means that the degree of a linear equation must be $0$ or $1$ for each of its variables. In this case, the degree of variable $y$ is $1$ and the degree of variable $x$ is $2$ .

Not Linear

Determine if Linear 2y=6x^2-x+3

Related Questions

Support LCMGCF.com by disabling your adblocker.