Determine if Linear 7x(y+2)=3-7y(9-x)

$7 x (y + 2) = 3 - 7 y (9 - x)$

Step 1

Solve the equation for $y$ .

Simplify $7 x (y + 2)$ .

Rewrite.

$0 + 0 + 7 x (y + 2) = 3 - 7 y (9 - x)$

Simplify by adding zeros.

$7 x (y + 2) = 3 - 7 y (9 - x)$

Apply the distributive property.

$7 x y + 7 x \cdot 2 = 3 - 7 y (9 - x)$

Multiply $2$ by $7$ .

$7 x y + 14 x = 3 - 7 y (9 - x)$

Simplify each term.

Apply the distributive property.

$7 x y + 14 x = 3 - 7 y \cdot 9 - 7 y (- x)$

Multiply $9$ by $- 7$ .

$7 x y + 14 x = 3 - 63 y - 7 y (- x)$

Rewrite using the commutative property of multiplication.

$7 x y + 14 x = 3 - 63 y - 7 \cdot - 1 y x$

Multiply $- 7$ by $- 1$ .

$7 x y + 14 x = 3 - 63 y + 7 y x$

Since $y$ is on the right side of the equation, switch the sides so it is on the left side of the equation.

$3 - 63 y + 7 y x = 7 x y + 14 x$

Move all terms containing $y$ to the left side of the equation.

Subtract $7 x y$ from both sides of the equation.

$3 - 63 y + 7 y x - 7 x y = 14 x$

Combine the opposite terms in $3 - 63 y + 7 y x - 7 x y$ .

Reorder the factors in the terms $7 y x$ and $- 7 x y$ .

$3 - 63 y + 7 x y - 7 x y = 14 x$

Subtract $7 x y$ from $7 x y$ .

$3 - 63 y + 0 = 14 x$

Add $3 - 63 y$ and $0$ .

$3 - 63 y = 14 x$

Subtract $3$ from both sides of the equation.

$- 63 y = 14 x - 3$

Divide each term in $- 63 y = 14 x - 3$ by $- 63$ and simplify.

Divide each term in $- 63 y = 14 x - 3$ by $- 63$ .

$\frac{- 63 y}{- 63} = \frac{14 x}{- 63} + \frac{- 3}{- 63}$

Simplify the left side.

Cancel the common factor of $- 63$ .

Cancel the common factor.

$\frac{- 63 y}{- 63} = \frac{14 x}{- 63} + \frac{- 3}{- 63}$

Divide $y$ by $1$ .

$y = \frac{14 x}{- 63} + \frac{- 3}{- 63}$

Simplify the right side.

Simplify each term.

Cancel the common factor of $14$ and $- 63$ .

Factor $7$ out of $14 x$ .

$y = \frac{7 (2 x)}{- 63} + \frac{- 3}{- 63}$

Cancel the common factors.

Factor $7$ out of $- 63$ .

$y = \frac{7 (2 x)}{7 (- 9)} + \frac{- 3}{- 63}$

Cancel the common factor.

$y = \frac{7 (2 x)}{7 \cdot - 9} + \frac{- 3}{- 63}$

Rewrite the expression.

$y = \frac{2 x}{- 9} + \frac{- 3}{- 63}$

Move the negative in front of the fraction.

$y = - \frac{2 x}{9} + \frac{- 3}{- 63}$

Cancel the common factor of $- 3$ and $- 63$ .

Factor $- 3$ out of $- 3$ .

$y = - \frac{2 x}{9} + \frac{- 3 (1)}{- 63}$

Cancel the common factors.

Factor $- 3$ out of $- 63$ .

$y = - \frac{2 x}{9} + \frac{- 3 \cdot 1}{- 3 \cdot 21}$

Cancel the common factor.

$y = - \frac{2 x}{9} + \frac{- 3 \cdot 1}{- 3 \cdot 21}$

Rewrite the expression.

$y = - \frac{2 x}{9} + \frac{1}{21}$

Step 2

A linear equation is an equation of a straight line, which means that the degree of a linear equation must be $0$ or $1$ for each of its variables. In this case, the degree of variable $y$ is $1$ and the degree of variable $x$ is $1$ .

Linear

Determine if Linear 7x(y+2)=3-7y(9-x)

Related Questions

Support LCMGCF.com by disabling your adblocker.