Determine if Odd, Even, or Neither g(x)=5x^4-2x^3

$g (x) = 5 x^{4} - 2 x^{3}$

Step 1

Find $f (- x)$ .

Find $g (- x)$ by substituting $- x$ for all occurrence of $x$ in $g (x)$ .

$g (- x) = 5 {(- x)}^{4} - 2 {(- x)}^{3}$

Simplify each term.

Apply the product rule to $- x$ .

$g (- x) = 5 ({(- 1)}^{4} x^{4}) - 2 {(- x)}^{3}$

Raise $- 1$ to the power of $4$ .

$g (- x) = 5 (1 x^{4}) - 2 {(- x)}^{3}$

Multiply $x^{4}$ by $1$ .

$g (- x) = 5 x^{4} - 2 {(- x)}^{3}$

Apply the product rule to $- x$ .

$g (- x) = 5 x^{4} - 2 ({(- 1)}^{3} x^{3})$

Raise $- 1$ to the power of $3$ .

$g (- x) = 5 x^{4} - 2 (- x^{3})$

Multiply $- 1$ by $- 2$ .

$g (- x) = 5 x^{4} + 2 x^{3}$

Step 2

A function is even if $f (- x) = f (x)$ .

Check if $f (- x) = f (x)$ .

Since $5 x^{4} + 2 x^{3}$ $\neq$ $5 x^{4} - 2 x^{3}$ , the function is not even.

The function is not even

Step 3

A function is odd if $f (- x) = - f (x)$ .

Find $- f (x)$ .

Multiply $5 x^{4} - 2 x^{3}$ by $- 1$ .

$- f (x) = - (5 x^{4} - 2 x^{3})$

Apply the distributive property.

$- f (x) = - (5 x^{4}) - (- 2 x^{3})$

Multiply.

Multiply $5$ by $- 1$ .

$- f (x) = - 5 x^{4} - (- 2 x^{3})$

Multiply $- 2$ by $- 1$ .

$- f (x) = - 5 x^{4} + 2 x^{3}$

Since $5 x^{4} + 2 x^{3}$ $\neq$ $- 5 x^{4} + 2 x^{3}$ , the function is not odd.

The function is not odd

Step 4

The function is neither odd nor even

Step 5