Determine if Odd, Even, or Neither x^4-3x^2+6

$x^{4} - 3 x^{2} + 6$

Step 1

Write $x^{4} - 3 x^{2} + 6$ as a function.

$f (x) = x^{4} - 3 x^{2} + 6$

Step 2

Find $f (- x)$ .

Find $f (- x)$ by substituting $- x$ for all occurrence of $x$ in $f (x)$ .

$f (- x) = {(- x)}^{4} - 3 {(- x)}^{2} + 6$

Simplify each term.

Apply the product rule to $- x$ .

$f (- x) = {(- 1)}^{4} x^{4} - 3 {(- x)}^{2} + 6$

Raise $- 1$ to the power of $4$ .

$f (- x) = 1 x^{4} - 3 {(- x)}^{2} + 6$

Multiply $x^{4}$ by $1$ .

$f (- x) = x^{4} - 3 {(- x)}^{2} + 6$

Apply the product rule to $- x$ .

$f (- x) = x^{4} - 3 ({(- 1)}^{2} x^{2}) + 6$

Raise $- 1$ to the power of $2$ .

$f (- x) = x^{4} - 3 (1 x^{2}) + 6$

Multiply $x^{2}$ by $1$ .

$f (- x) = x^{4} - 3 x^{2} + 6$

Step 3

A function is even if $f (- x) = f (x)$ .

Check if $f (- x) = f (x)$ .

Since $x^{4} - 3 x^{2} + 6 = x^{4} - 3 x^{2} + 6$ , the function is even.

The function is even

Step 4