Determine if Perpendicular x+y=8 and y=-x-1

$x + y = 8$ and $y = - x - 1$

Step 1

Find the slope and y-intercept of the first equation.

Rewrite in slope-intercept form.

The slope-intercept form is $y = m x + b$ , where $m$ is the slope and $b$ is the y-intercept.

$y = m x + b$

Subtract $x$ from both sides of the equation.

$y = 8 - x$

Reorder $8$ and $- x$ .

$y = - x + 8$

Find the values of $m$ and $b$ using the form $y = m x + b$ .

$m_{1} = - 1$

$b = 8$

$m_{1} = - 1$

$b = 8$

Step 2

Use the slope-intercept form to find the slope and y-intercept.

The slope-intercept form is $y = m x + b$ , where $m$ is the slope and $b$ is the y-intercept.

$y = m x + b$

Find the values of $m$ and $b$ using the form $y = m x + b$ .

$m_{2} = - 1$

$b = - 1$

$m_{2} = - 1$

$b = - 1$

Step 3

Compare the slopes $m$ of the two equations.

$m_{1} = - 1, m_{2} = - 1$

Step 4

Compare the decimal form of one slope with the negative reciprocal of the other slope. If they are equal, then the lines are perpendicular. If the they are not equal, then the lines are not perpendicular.

$m_{1} = - 1, m_{2} = 1$

Step 5

The equations are not perpendicular because the slopes of the two lines are not negative reciprocals.

Not Perpendicular

Step 6

Determine if Perpendicular x+y=8 and y=-x-1

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