Determine the Nature of the Roots Using the Discriminant x^2+14x-49=0

$x^{2} + 14 x - 49 = 0$

The discriminant of a quadratic is the expression inside the radical of the quadratic formula.

$b^{2} - 4 (a c)$

Substitute in the values of $a$ , $b$ , and $c$ .

$14^{2} - 4 (1 \cdot - 49)$

Evaluate the result to find the discriminant.

Simplify each term.

Raise $14$ to the power of $2$ .

$196 - 4 (1 \cdot - 49)$

Multiply $- 49$ by $1$ .

$196 - 4 \cdot - 49$

Multiply $- 4$ by $- 49$ .

$196 + 196$

Add $196$ and $196$ .

$392$

The nature of the roots of the quadratic can fall into one of three categories depending on the value of the discriminant $(Δ)$ :

$Δ > 0$ means there are $2$ distinct real roots.

$Δ = 0$ means there are $2$ equal real roots, or $1$ distinct real root.

$Δ < 0$ means there are no real roots, but $2$ complex roots.

Since the discriminant is greater than $0$ , there are two real roots.

Two Real Roots