Divide (1/9)÷(-2/3)

$\frac{1}{9} \div (- \frac{2}{3})$

To divide by a fraction, multiply by its reciprocal.

$\frac{1}{9} (- \frac{3}{2})$

Cancel the common factor of $3$ .

Move the leading negative in $- \frac{3}{2}$ into the numerator.

$\frac{1}{9} \cdot \frac{- 3}{2}$

Factor $3$ out of $9$ .

$\frac{1}{3 (3)} \cdot \frac{- 3}{2}$

Factor $3$ out of $- 3$ .

$\frac{1}{3 \cdot 3} \cdot \frac{3 \cdot - 1}{2}$

Cancel the common factor.

$\frac{1}{3 \cdot 3} \cdot \frac{3 \cdot - 1}{2}$

Rewrite the expression.

$\frac{1}{3} \cdot \frac{- 1}{2}$

Multiply $\frac{1}{3}$ by $\frac{- 1}{2}$ .

$\frac{- 1}{3 \cdot 2}$

Multiply $3$ by $2$ .

$\frac{- 1}{6}$

Move the negative in front of the fraction.

$- \frac{1}{6}$

The result can be shown in multiple forms.

Exact Form:

$- \frac{1}{6}$

Decimal Form:

$- 0.1\overline{6}$