Divide (10b)/(2b+8)

$\frac{10 b}{2 b + 8}$

Step 1

Set up the polynomials to be divided. If there is not a term for every exponent, insert one with a value of $0$ .

$2 b$

$8$

$10 b$

$0$

Step 2

Divide the highest order term in the dividend $10 b$ by the highest order term in divisor $2 b$ .

					$5$
	$2 b$	+	$8$		$10 b$	+	$0$

Step 3

Multiply the new quotient term by the divisor.

Step 4

The expression needs to be subtracted from the dividend, so change all the signs in $10 b + 40$

Step 5

After changing the signs, add the last dividend from the multiplied polynomial to find the new dividend.

Step 6

The final answer is the quotient plus the remainder over the divisor.

$5 - \frac{40}{2 b + 8}$