Divide (16 cube root of 24)/(2 cube root of 3)

$\frac{16 \sqrt[3]{24}}{2 \sqrt[3]{3}}$

Step 1

Cancel the common factor of $16$ and $2$ .

Factor $2$ out of $16 \sqrt[3]{24}$ .

$\frac{2 (8 \sqrt[3]{24})}{2 \sqrt[3]{3}}$

Cancel the common factors.

Factor $2$ out of $2 \sqrt[3]{3}$ .

$\frac{2 (8 \sqrt[3]{24})}{2 (\sqrt[3]{3})}$

Cancel the common factor.

$\frac{2 (8 \sqrt[3]{24})}{2 \sqrt[3]{3}}$

Rewrite the expression.

$\frac{8 \sqrt[3]{24}}{\sqrt[3]{3}}$

Step 2

Combine $\sqrt[3]{24}$ and $\sqrt[3]{3}$ into a single radical.

$8 \sqrt[3]{\frac{24}{3}}$

Step 3

Divide $24$ by $3$ .

$8 \sqrt[3]{8}$

Step 4

Rewrite $8$ as $2^{3}$ .

$8 \sqrt[3]{2^{3}}$

Step 5

Pull terms out from under the radical, assuming real numbers.

$8 \cdot 2$

Step 6

Multiply $8$ by $2$ .

$16$