Divide (2h^3j^-3k^4)/(3jk)

$\frac{2 h^{3} j^{- 3} k^{4}}{3 j k}$

Step 1

Move $j^{- 3}$ to the denominator using the negative exponent rule $b^{- n} = \frac{1}{b^{n}}$ .

$\frac{2 h^{3} k^{4}}{3 j k j^{3}}$

Step 2

Multiply $j$ by $j^{3}$ by adding the exponents.

Move $j^{3}$ .

$\frac{2 h^{3} k^{4}}{3 (j^{3} j) k}$

Multiply $j^{3}$ by $j$ .

Raise $j$ to the power of $1$ .

$\frac{2 h^{3} k^{4}}{3 (j^{3} j^{1}) k}$

Use the power rule $a^{m} a^{n} = a^{m + n}$ to combine exponents.

$\frac{2 h^{3} k^{4}}{3 j^{3 + 1} k}$

Add $3$ and $1$ .

$\frac{2 h^{3} k^{4}}{3 j^{4} k}$

Step 3

Cancel the common factor of $k^{4}$ and $k$ .

Factor $k$ out of $2 h^{3} k^{4}$ .

$\frac{k (2 h^{3} k^{3})}{3 j^{4} k}$

Cancel the common factors.

Factor $k$ out of $3 j^{4} k$ .

$\frac{k (2 h^{3} k^{3})}{k (3 j^{4})}$

Cancel the common factor.

$\frac{k (2 h^{3} k^{3})}{k (3 j^{4})}$

Rewrite the expression.

$\frac{2 h^{3} k^{3}}{3 j^{4}}$