Divide (2x^3+7)/x

$\frac{2 x^{3} + 7}{x}$

Step 1

Split the fraction $\frac{2 x^{3} + 7}{x}$ into two fractions.

$\frac{2 x^{3}}{x} + \frac{7}{x}$

Step 2

Cancel the common factor of $x^{3}$ and $x$ .

Factor $x$ out of $2 x^{3}$ .

$\frac{x (2 x^{2})}{x} + \frac{7}{x}$

Cancel the common factors.

Raise $x$ to the power of $1$ .

$\frac{x (2 x^{2})}{x^{1}} + \frac{7}{x}$

Factor $x$ out of $x^{1}$ .

$\frac{x (2 x^{2})}{x \cdot 1} + \frac{7}{x}$

Cancel the common factor.

$\frac{x (2 x^{2})}{x \cdot 1} + \frac{7}{x}$

Rewrite the expression.

$\frac{2 x^{2}}{1} + \frac{7}{x}$

Divide $2 x^{2}$ by $1$ .

$2 x^{2} + \frac{7}{x}$