Divide (2x^3+9x^2+14x+5)/(2x+1)

$\frac{2 x^{3} + 9 x^{2} + 14 x + 5}{2 x + 1}$

Step 1

Set up the polynomials to be divided. If there is not a term for every exponent, insert one with a value of $0$ .

$2 x$

$1$

$2 x^{3}$

$9 x^{2}$

$14 x$

$5$

Step 2

Divide the highest order term in the dividend $2 x^{3}$ by the highest order term in divisor $2 x$ .

					$x^{2}$
	$2 x$	+	$1$		$2 x^{3}$	+	$9 x^{2}$	+	$14 x$	+	$5$

Step 3

Multiply the new quotient term by the divisor.

				$x^{2}$
$2 x$	+	$1$		$2 x^{3}$	+	$9 x^{2}$	+	$14 x$	+	$5$
			+	$2 x^{3}$	+	$x^{2}$

Step 4

The expression needs to be subtracted from the dividend, so change all the signs in $2 x^{3} + x^{2}$

				$x^{2}$
$2 x$	+	$1$		$2 x^{3}$	+	$9 x^{2}$	+	$14 x$	+	$5$
			-	$2 x^{3}$	-	$x^{2}$

Step 5

After changing the signs, add the last dividend from the multiplied polynomial to find the new dividend.

				$x^{2}$
$2 x$	+	$1$		$2 x^{3}$	+	$9 x^{2}$	+	$14 x$	+	$5$
			-	$2 x^{3}$	-	$x^{2}$
					+	$8 x^{2}$

Step 6

Pull the next terms from the original dividend down into the current dividend.

				$x^{2}$
$2 x$	+	$1$		$2 x^{3}$	+	$9 x^{2}$	+	$14 x$	+	$5$
			-	$2 x^{3}$	-	$x^{2}$
					+	$8 x^{2}$	+	$14 x$

Step 7

Divide the highest order term in the dividend $8 x^{2}$ by the highest order term in divisor $2 x$ .

				$x^{2}$	+	$4 x$
$2 x$	+	$1$		$2 x^{3}$	+	$9 x^{2}$	+	$14 x$	+	$5$
			-	$2 x^{3}$	-	$x^{2}$
					+	$8 x^{2}$	+	$14 x$

Step 8

Multiply the new quotient term by the divisor.

				$x^{2}$	+	$4 x$
$2 x$	+	$1$		$2 x^{3}$	+	$9 x^{2}$	+	$14 x$	+	$5$
			-	$2 x^{3}$	-	$x^{2}$
					+	$8 x^{2}$	+	$14 x$
					+	$8 x^{2}$	+	$4 x$

Step 9

The expression needs to be subtracted from the dividend, so change all the signs in $8 x^{2} + 4 x$

				$x^{2}$	+	$4 x$
$2 x$	+	$1$		$2 x^{3}$	+	$9 x^{2}$	+	$14 x$	+	$5$
			-	$2 x^{3}$	-	$x^{2}$
					+	$8 x^{2}$	+	$14 x$
					-	$8 x^{2}$	-	$4 x$

Step 10

After changing the signs, add the last dividend from the multiplied polynomial to find the new dividend.

				$x^{2}$	+	$4 x$
$2 x$	+	$1$		$2 x^{3}$	+	$9 x^{2}$	+	$14 x$	+	$5$
			-	$2 x^{3}$	-	$x^{2}$
					+	$8 x^{2}$	+	$14 x$
					-	$8 x^{2}$	-	$4 x$
							+	$10 x$

Step 11

Pull the next terms from the original dividend down into the current dividend.

				$x^{2}$	+	$4 x$
$2 x$	+	$1$		$2 x^{3}$	+	$9 x^{2}$	+	$14 x$	+	$5$
			-	$2 x^{3}$	-	$x^{2}$
					+	$8 x^{2}$	+	$14 x$
					-	$8 x^{2}$	-	$4 x$
							+	$10 x$	+	$5$

Step 12

Divide the highest order term in the dividend $10 x$ by the highest order term in divisor $2 x$ .

				$x^{2}$	+	$4 x$	+	$5$
$2 x$	+	$1$		$2 x^{3}$	+	$9 x^{2}$	+	$14 x$	+	$5$
			-	$2 x^{3}$	-	$x^{2}$
					+	$8 x^{2}$	+	$14 x$
					-	$8 x^{2}$	-	$4 x$
							+	$10 x$	+	$5$

Step 13

Multiply the new quotient term by the divisor.

				$x^{2}$	+	$4 x$	+	$5$
$2 x$	+	$1$		$2 x^{3}$	+	$9 x^{2}$	+	$14 x$	+	$5$
			-	$2 x^{3}$	-	$x^{2}$
					+	$8 x^{2}$	+	$14 x$
					-	$8 x^{2}$	-	$4 x$
							+	$10 x$	+	$5$
							+	$10 x$	+	$5$

Step 14

The expression needs to be subtracted from the dividend, so change all the signs in $10 x + 5$

				$x^{2}$	+	$4 x$	+	$5$
$2 x$	+	$1$		$2 x^{3}$	+	$9 x^{2}$	+	$14 x$	+	$5$
			-	$2 x^{3}$	-	$x^{2}$
					+	$8 x^{2}$	+	$14 x$
					-	$8 x^{2}$	-	$4 x$
							+	$10 x$	+	$5$
							-	$10 x$	-	$5$

Step 15

After changing the signs, add the last dividend from the multiplied polynomial to find the new dividend.

				$x^{2}$	+	$4 x$	+	$5$
$2 x$	+	$1$		$2 x^{3}$	+	$9 x^{2}$	+	$14 x$	+	$5$
			-	$2 x^{3}$	-	$x^{2}$
					+	$8 x^{2}$	+	$14 x$
					-	$8 x^{2}$	-	$4 x$
							+	$10 x$	+	$5$
							-	$10 x$	-	$5$
										$0$

Step 16

Since the remander is $0$ , the final answer is the quotient.

$x^{2} + 4 x + 5$

Divide (2x^3+9x^2+14x+5)/(2x+1)

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