Divide (2x^4+4x^2-17-6x^3)÷(-x^2+2x-3)

$(2 x^{4} + 4 x^{2} - 17 - 6 x^{3}) \div (- x^{2} + 2 x - 3)$

Expand $2 x^{4} + 4 x^{2} - 17 - 6 x^{3}$ .

Move $- 17$ .

$\frac{2 x^{4} + 4 x^{2} - 6 x^{3} - 17}{- x^{2} + 2 x - 3}$

Move $4 x^{2}$ .

$\frac{2 x^{4} - 6 x^{3} + 4 x^{2} - 17}{- x^{2} + 2 x - 3}$

Set up the polynomials to be divided. If there is not a term for every exponent, insert one with a value of $0$ .

$x^{2}$

$2 x$

$3$

$2 x^{4}$

$6 x^{3}$

$4 x^{2}$

$0 x$

$17$

Divide the highest order term in the dividend $2 x^{4}$ by the highest order term in divisor $- x^{2}$ .

						-	$2 x^{2}$
-	$x^{2}$	+	$2 x$	-	$3$		$2 x^{4}$	-	$6 x^{3}$	+	$4 x^{2}$	+	$0 x$	-	$17$

Multiply the new quotient term by the divisor.

$2 x^{2}$

$x^{2}$

$2 x$

$3$

$2 x^{4}$

$6 x^{3}$

$4 x^{2}$

$0 x$

$17$

$2 x^{4}$

$4 x^{3}$

$6 x^{2}$

The expression needs to be subtracted from the dividend, so change all the signs in $2 x^{4} - 4 x^{3} + 6 x^{2}$

$2 x^{2}$

$x^{2}$

$2 x$

$3$

$2 x^{4}$

$6 x^{3}$

$4 x^{2}$

$0 x$

$17$

$2 x^{4}$

$4 x^{3}$

$6 x^{2}$

After changing the signs, add the last dividend from the multiplied polynomial to find the new dividend.

						-	$2 x^{2}$
-	$x^{2}$	+	$2 x$	-	$3$		$2 x^{4}$	-	$6 x^{3}$	+	$4 x^{2}$	+	$0 x$	-	$17$
						-	$2 x^{4}$	+	$4 x^{3}$	-	$6 x^{2}$
								-	$2 x^{3}$	-	$2 x^{2}$

Pull the next terms from the original dividend down into the current dividend.

$2 x^{2}$

$x^{2}$

$2 x$

$3$

$2 x^{4}$

$6 x^{3}$

$4 x^{2}$

$0 x$

$17$

$2 x^{4}$

$4 x^{3}$

$6 x^{2}$

$2 x^{3}$

$2 x^{2}$

$0 x$

Divide the highest order term in the dividend $- 2 x^{3}$ by the highest order term in divisor $- x^{2}$ .

$2 x^{2}$

$2 x$

$x^{2}$

$2 x$

$3$

$2 x^{4}$

$6 x^{3}$

$4 x^{2}$

$0 x$

$17$

$2 x^{4}$

$4 x^{3}$

$6 x^{2}$

$2 x^{3}$

$2 x^{2}$

$0 x$

Multiply the new quotient term by the divisor.

$2 x^{2}$

$2 x$

$x^{2}$

$2 x$

$3$

$2 x^{4}$

$6 x^{3}$

$4 x^{2}$

$0 x$

$17$

$2 x^{4}$

$4 x^{3}$

$6 x^{2}$

$2 x^{3}$

$2 x^{2}$

$0 x$

$2 x^{3}$

$4 x^{2}$

$6 x$

The expression needs to be subtracted from the dividend, so change all the signs in $- 2 x^{3} + 4 x^{2} - 6 x$

$2 x^{2}$

$2 x$

$x^{2}$

$2 x$

$3$

$2 x^{4}$

$6 x^{3}$

$4 x^{2}$

$0 x$

$17$

$2 x^{4}$

$4 x^{3}$

$6 x^{2}$

$2 x^{3}$

$2 x^{2}$

$0 x$

$2 x^{3}$

$4 x^{2}$

$6 x$

After changing the signs, add the last dividend from the multiplied polynomial to find the new dividend.

$2 x^{2}$

$2 x$

$x^{2}$

$2 x$

$3$

$2 x^{4}$

$6 x^{3}$

$4 x^{2}$

$0 x$

$17$

$2 x^{4}$

$4 x^{3}$

$6 x^{2}$

$2 x^{3}$

$2 x^{2}$

$0 x$

$2 x^{3}$

$4 x^{2}$

$6 x$

$6 x^{2}$

$6 x$

Pull the next terms from the original dividend down into the current dividend.

$2 x^{2}$

$2 x$

$x^{2}$

$2 x$

$3$

$2 x^{4}$

$6 x^{3}$

$4 x^{2}$

$0 x$

$17$

$2 x^{4}$

$4 x^{3}$

$6 x^{2}$

$2 x^{3}$

$2 x^{2}$

$0 x$

$2 x^{3}$

$4 x^{2}$

$6 x$

$6 x^{2}$

$6 x$

$17$

Divide the highest order term in the dividend $- 6 x^{2}$ by the highest order term in divisor $- x^{2}$ .

$2 x^{2}$

$2 x$

$6$

$x^{2}$

$2 x$

$3$

$2 x^{4}$

$6 x^{3}$

$4 x^{2}$

$0 x$

$17$

$2 x^{4}$

$4 x^{3}$

$6 x^{2}$

$2 x^{3}$

$2 x^{2}$

$0 x$

$2 x^{3}$

$4 x^{2}$

$6 x$

$6 x^{2}$

$6 x$

$17$

Multiply the new quotient term by the divisor.

$2 x^{2}$

$2 x$

$6$

$x^{2}$

$2 x$

$3$

$2 x^{4}$

$6 x^{3}$

$4 x^{2}$

$0 x$

$17$

$2 x^{4}$

$4 x^{3}$

$6 x^{2}$

$2 x^{3}$

$2 x^{2}$

$0 x$

$2 x^{3}$

$4 x^{2}$

$6 x$

$6 x^{2}$

$6 x$

$17$

$6 x^{2}$

$12 x$

$18$

The expression needs to be subtracted from the dividend, so change all the signs in $- 6 x^{2} + 12 x - 18$

$2 x^{2}$

$2 x$

$6$

$x^{2}$

$2 x$

$3$

$2 x^{4}$

$6 x^{3}$

$4 x^{2}$

$0 x$

$17$

$2 x^{4}$

$4 x^{3}$

$6 x^{2}$

$2 x^{3}$

$2 x^{2}$

$0 x$

$2 x^{3}$

$4 x^{2}$

$6 x$

$6 x^{2}$

$6 x$

$17$

$6 x^{2}$

$12 x$

$18$

After changing the signs, add the last dividend from the multiplied polynomial to find the new dividend.

$2 x^{2}$

$2 x$

$6$

$x^{2}$

$2 x$

$3$

$2 x^{4}$

$6 x^{3}$

$4 x^{2}$

$0 x$

$17$

$2 x^{4}$

$4 x^{3}$

$6 x^{2}$

$2 x^{3}$

$2 x^{2}$

$0 x$

$2 x^{3}$

$4 x^{2}$

$6 x$

$6 x^{2}$

$6 x$

$17$

$6 x^{2}$

$12 x$

$18$

$6 x$

$1$

The final answer is the quotient plus the remainder over the divisor.

$- 2 x^{2} + 2 x + 6 + \frac{- 6 x + 1}{- x^{2} + 2 x - 3}$

Divide (2x^4+4x^2-17-6x^3)÷(-x^2+2x-3)

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