Divide (2x-8)/(2x+2)

$\frac{2 x - 8}{2 x + 2}$

Step 1

Set up the polynomials to be divided. If there is not a term for every exponent, insert one with a value of $0$ .

$2 x$

$2$

$2 x$

$8$

Step 2

Divide the highest order term in the dividend $2 x$ by the highest order term in divisor $2 x$ .

					$1$
	$2 x$	+	$2$		$2 x$	-	$8$

Step 3

Multiply the new quotient term by the divisor.

Step 4

The expression needs to be subtracted from the dividend, so change all the signs in $2 x + 2$

Step 5

After changing the signs, add the last dividend from the multiplied polynomial to find the new dividend.

Step 6

The final answer is the quotient plus the remainder over the divisor.

$1 - \frac{10}{2 x + 2}$