Divide ((3x-1)/(6x^4+x^3+8x^2+9x-4))

$(\frac{3 x - 1}{6 x^{4} + x^{3} + 8 x^{2} + 9 x - 4})$

Step 1

Remove parentheses.

$\frac{3 x - 1}{6 x^{4} + x^{3} + 8 x^{2} + 9 x - 4}$

Step 2

Split the fraction $\frac{3 x - 1}{6 x^{4} + x^{3} + 8 x^{2} + 9 x - 4}$ into two fractions.

$\frac{3 x}{6 x^{4} + x^{3} + 8 x^{2} + 9 x - 4} + \frac{- 1}{6 x^{4} + x^{3} + 8 x^{2} + 9 x - 4}$

Step 3

Move the negative in front of the fraction.

$\frac{3 x}{6 x^{4} + x^{3} + 8 x^{2} + 9 x - 4} - \frac{1}{6 x^{4} + x^{3} + 8 x^{2} + 9 x - 4}$