Divide (3x^3y+5x^2y^2-2xy)/(xy)

$\frac{3 x^{3} y + 5 x^{2} y^{2} - 2 x y}{x y}$

Step 1

Factor $x y$ out of $3 x^{3} y + 5 x^{2} y^{2} - 2 x y$ .

Factor $x y$ out of $3 x^{3} y$ .

$\frac{x y (3 x^{2}) + 5 x^{2} y^{2} - 2 x y}{x y}$

Factor $x y$ out of $5 x^{2} y^{2}$ .

$\frac{x y (3 x^{2}) + x y (5 x y) - 2 x y}{x y}$

Factor $x y$ out of $- 2 x y$ .

$\frac{x y (3 x^{2}) + x y (5 x y) + x y (- 2)}{x y}$

Factor $x y$ out of $x y (3 x^{2}) + x y (5 x y)$ .

$\frac{x y (3 x^{2} + 5 x y) + x y (- 2)}{x y}$

Factor $x y$ out of $x y (3 x^{2} + 5 x y) + x y (- 2)$ .

$\frac{x y (3 x^{2} + 5 x y - 2)}{x y}$

Step 2

Cancel the common factor of $x$ .

Cancel the common factor.

$\frac{x y (3 x^{2} + 5 x y - 2)}{x y}$

Rewrite the expression.

$\frac{y (3 x^{2} + 5 x y - 2)}{y}$

Step 3

Cancel the common factor of $y$ .

Cancel the common factor.

$\frac{y (3 x^{2} + 5 x y - 2)}{y}$

Divide $3 x^{2} + 5 x y - 2$ by $1$ .

$3 x^{2} + 5 x y - 2$