Divide ((5n^2(m^2+2m-3))/(10n(m^2-3m+2)))÷((n^2(m^2-3m-18))/(4n^2(m^2-8m+12)))

$\frac{5 n^{2} (m^{2} + 2 m - 3)}{10 n (m^{2} - 3 m + 2)} \div \frac{n^{2} (m^{2} - 3 m - 18)}{4 n^{2} (m^{2} - 8 m + 12)}$

Step 1

To divide by a fraction, multiply by its reciprocal.

$\frac{5 n^{2} (m^{2} + 2 m - 3)}{10 n (m^{2} - 3 m + 2)} \cdot \frac{4 n^{2} (m^{2} - 8 m + 12)}{n^{2} (m^{2} - 3 m - 18)}$

Step 2

Combine.

$\frac{5 n^{2} (m^{2} + 2 m - 3) (4 n^{2} (m^{2} - 8 m + 12))}{10 n (m^{2} - 3 m + 2) (n^{2} (m^{2} - 3 m - 18))}$

Step 3

Multiply $n^{2}$ by $n^{2}$ by adding the exponents.

Move $n^{2}$ .

$\frac{5 (n^{2} n^{2}) (m^{2} + 2 m - 3) (4 (m^{2} - 8 m + 12))}{10 n (m^{2} - 3 m + 2) (n^{2} (m^{2} - 3 m - 18))}$

Use the power rule $a^{m} a^{n} = a^{m + n}$ to combine exponents.

$\frac{5 n^{2 + 2} (m^{2} + 2 m - 3) (4 (m^{2} - 8 m + 12))}{10 n (m^{2} - 3 m + 2) (n^{2} (m^{2} - 3 m - 18))}$

Add $2$ and $2$ .

$\frac{5 n^{4} (m^{2} + 2 m - 3) (4 (m^{2} - 8 m + 12))}{10 n (m^{2} - 3 m + 2) (n^{2} (m^{2} - 3 m - 18))}$

Step 4

Multiply $n$ by $n^{2}$ by adding the exponents.

Move $n^{2}$ .

$\frac{5 n^{4} (m^{2} + 2 m - 3) (4 (m^{2} - 8 m + 12))}{10 (n^{2} n) (m^{2} - 3 m + 2) (m^{2} - 3 m - 18)}$

Multiply $n^{2}$ by $n$ .

Raise $n$ to the power of $1$ .

$\frac{5 n^{4} (m^{2} + 2 m - 3) (4 (m^{2} - 8 m + 12))}{10 (n^{2} n^{1}) (m^{2} - 3 m + 2) (m^{2} - 3 m - 18)}$

Use the power rule $a^{m} a^{n} = a^{m + n}$ to combine exponents.

$\frac{5 n^{4} (m^{2} + 2 m - 3) (4 (m^{2} - 8 m + 12))}{10 n^{2 + 1} (m^{2} - 3 m + 2) (m^{2} - 3 m - 18)}$

Add $2$ and $1$ .

$\frac{5 n^{4} (m^{2} + 2 m - 3) (4 (m^{2} - 8 m + 12))}{10 n^{3} (m^{2} - 3 m + 2) (m^{2} - 3 m - 18)}$

Step 5

Cancel the common factor of $5$ and $10$ .

Factor $5$ out of $5 n^{4} (m^{2} + 2 m - 3) (4 (m^{2} - 8 m + 12))$ .

$\frac{5 ((n^{4} (m^{2} + 2 m - 3)) (4 (m^{2} - 8 m + 12)))}{10 n^{3} (m^{2} - 3 m + 2) (m^{2} - 3 m - 18)}$

Cancel the common factors.

Factor $5$ out of $10 n^{3} (m^{2} - 3 m + 2) (m^{2} - 3 m - 18)$ .

$\frac{5 ((n^{4} (m^{2} + 2 m - 3)) (4 (m^{2} - 8 m + 12)))}{5 (2 n^{3} (m^{2} - 3 m + 2) (m^{2} - 3 m - 18))}$

Cancel the common factor.

$\frac{5 ((n^{4} (m^{2} + 2 m - 3)) (4 (m^{2} - 8 m + 12)))}{5 (2 n^{3} (m^{2} - 3 m + 2) (m^{2} - 3 m - 18))}$

Rewrite the expression.

$\frac{(n^{4} (m^{2} + 2 m - 3)) (4 (m^{2} - 8 m + 12))}{2 n^{3} (m^{2} - 3 m + 2) (m^{2} - 3 m - 18)}$

Step 6

Cancel the common factor of $n^{4}$ and $n^{3}$ .

Factor $n^{3}$ out of $(n^{4} (m^{2} + 2 m - 3)) (4 (m^{2} - 8 m + 12))$ .

$\frac{n^{3} ((n (m^{2} + 2 m - 3)) (4 (m^{2} - 8 m + 12)))}{2 n^{3} (m^{2} - 3 m + 2) (m^{2} - 3 m - 18)}$

Cancel the common factors.

Factor $n^{3}$ out of $2 n^{3} (m^{2} - 3 m + 2) (m^{2} - 3 m - 18)$ .

$\frac{n^{3} ((n (m^{2} + 2 m - 3)) (4 (m^{2} - 8 m + 12)))}{n^{3} ((2 (m^{2} - 3 m + 2)) (m^{2} - 3 m - 18))}$

Cancel the common factor.

$\frac{n^{3} ((n (m^{2} + 2 m - 3)) (4 (m^{2} - 8 m + 12)))}{n^{3} ((2 (m^{2} - 3 m + 2)) (m^{2} - 3 m - 18))}$

Rewrite the expression.

$\frac{(n (m^{2} + 2 m - 3)) (4 (m^{2} - 8 m + 12))}{(2 (m^{2} - 3 m + 2)) (m^{2} - 3 m - 18)}$

Step 7

Cancel the common factor of $4$ and $2$ .

Factor $2$ out of $(n (m^{2} + 2 m - 3)) (4 (m^{2} - 8 m + 12))$ .

$\frac{2 (n (m^{2} + 2 m - 3) (2 (m^{2} - 8 m + 12)))}{(2 (m^{2} - 3 m + 2)) (m^{2} - 3 m - 18)}$

Cancel the common factors.

Factor $2$ out of $(2 (m^{2} - 3 m + 2)) (m^{2} - 3 m - 18)$ .

$\frac{2 (n (m^{2} + 2 m - 3) (2 (m^{2} - 8 m + 12)))}{2 ((m^{2} - 3 m + 2) (m^{2} - 3 m - 18))}$

Cancel the common factor.

$\frac{2 (n (m^{2} + 2 m - 3) (2 (m^{2} - 8 m + 12)))}{2 ((m^{2} - 3 m + 2) (m^{2} - 3 m - 18))}$

Rewrite the expression.

$\frac{n (m^{2} + 2 m - 3) (2 (m^{2} - 8 m + 12))}{(m^{2} - 3 m + 2) (m^{2} - 3 m - 18)}$

Step 8

Simplify the numerator.

Rewrite.

$\frac{5 n^{2} (m^{2} + 2 m - 3) (4 n^{2} (m^{2} - 8 m + 12))}{(m^{2} - 3 m + 2) (m^{2} - 3 m - 18)}$

Multiply $n^{2}$ by $n^{2}$ by adding the exponents.

Move $n^{2}$ .

$\frac{5 (n^{2} n^{2}) (m^{2} + 2 m - 3) (4 (m^{2} - 8 m + 12))}{(m^{2} - 3 m + 2) (m^{2} - 3 m - 18)}$

Use the power rule $a^{m} a^{n} = a^{m + n}$ to combine exponents.

$\frac{5 n^{2 + 2} (m^{2} + 2 m - 3) (4 (m^{2} - 8 m + 12))}{(m^{2} - 3 m + 2) (m^{2} - 3 m - 18)}$

Add $2$ and $2$ .

$\frac{5 n^{4} (m^{2} + 2 m - 3) (4 (m^{2} - 8 m + 12))}{(m^{2} - 3 m + 2) (m^{2} - 3 m - 18)}$

Rewrite.

$\frac{n^{2} n^{2} (m^{2} + 2 m - 3) (4 (m^{2} - 8 m + 12))}{(m^{2} - 3 m + 2) (m^{2} - 3 m - 18)}$

Use the power rule $a^{m} a^{n} = a^{m + n}$ to combine exponents.

$\frac{n^{2 + 2} (m^{2} + 2 m - 3) (4 (m^{2} - 8 m + 12))}{(m^{2} - 3 m + 2) (m^{2} - 3 m - 18)}$

Add $2$ and $2$ .

$\frac{n^{4} (m^{2} + 2 m - 3) (4 (m^{2} - 8 m + 12))}{(m^{2} - 3 m + 2) (m^{2} - 3 m - 18)}$

Multiply $n^{4} (m^{2} + 2 m - 3)$ by $4 (m^{2} - 8 m + 12)$ .

$\frac{(n^{4} (m^{2} + 2 m - 3)) (4 (m^{2} - 8 m + 12))}{(m^{2} - 3 m + 2) (m^{2} - 3 m - 18)}$

Factor $n^{3}$ out of $n^{4}$ .

$\frac{n^{3} n (m^{2} + 2 m - 3) (4 (m^{2} - 8 m + 12))}{(m^{2} - 3 m + 2) (m^{2} - 3 m - 18)}$

Rewrite.

$\frac{n^{1} (m^{2} + 2 m - 3) (4 (m^{2} - 8 m + 12))}{(m^{2} - 3 m + 2) (m^{2} - 3 m - 18)}$

Simplify.

$\frac{n (m^{2} + 2 m - 3) (4 (m^{2} - 8 m + 12))}{(m^{2} - 3 m + 2) (m^{2} - 3 m - 18)}$

Multiply $n (m^{2} + 2 m - 3)$ by $4 (m^{2} - 8 m + 12)$ .

$\frac{(n (m^{2} + 2 m - 3)) (4 (m^{2} - 8 m + 12))}{(m^{2} - 3 m + 2) (m^{2} - 3 m - 18)}$

Factor $2$ out of $4$ .

$\frac{n (m^{2} + 2 m - 3) (2 (2) (m^{2} - 8 m + 12))}{(m^{2} - 3 m + 2) (m^{2} - 3 m - 18)}$

Rewrite.

$\frac{n (m^{2} + 2 m - 3) (\frac{4}{2} (m^{2} - 8 m + 12))}{(m^{2} - 3 m + 2) (m^{2} - 3 m - 18)}$

Divide $4$ by $2$ .

$\frac{n (m^{2} + 2 m - 3) (2 (m^{2} - 8 m + 12))}{(m^{2} - 3 m + 2) (m^{2} - 3 m - 18)}$

Remove unnecessary parentheses.

$\frac{n (m^{2} + 2 m - 3) \cdot 2 (m^{2} - 8 m + 12)}{(m^{2} - 3 m + 2) (m^{2} - 3 m - 18)}$

Factor $m^{2} + 2 m - 3$ using the AC method.

Consider the form $x^{2} + b x + c$ . Find a pair of integers whose product is $c$ and whose sum is $b$ . In this case, whose product is $- 3$ and whose sum is $2$ .

$- 1, 3$

Write the factored form using these integers.

$\frac{n ((m - 1) (m + 3)) \cdot 2 (m^{2} - 8 m + 12)}{(m^{2} - 3 m + 2) (m^{2} - 3 m - 18)}$

$\frac{n (m - 1) (m + 3) \cdot 2 (m^{2} - 8 m + 12)}{(m^{2} - 3 m + 2) (m^{2} - 3 m - 18)}$

Factor $m^{2} - 8 m + 12$ using the AC method.

Consider the form $x^{2} + b x + c$ . Find a pair of integers whose product is $c$ and whose sum is $b$ . In this case, whose product is $12$ and whose sum is $- 8$ .

$- 6, - 2$

Write the factored form using these integers.

$\frac{n (m - 1) (m + 3) \cdot 2 ((m - 6) (m - 2))}{(m^{2} - 3 m + 2) (m^{2} - 3 m - 18)}$

Step 9

Simplify the denominator.

Factor $m^{2} - 3 m + 2$ using the AC method.

Consider the form $x^{2} + b x + c$ . Find a pair of integers whose product is $c$ and whose sum is $b$ . In this case, whose product is $2$ and whose sum is $- 3$ .

$- 2, - 1$

Write the factored form using these integers.

$\frac{n (m - 1) (m + 3) \cdot 2 ((m - 6) (m - 2))}{(m - 2) (m - 1) (m^{2} - 3 m - 18)}$

Factor $m^{2} - 3 m - 18$ using the AC method.

Consider the form $x^{2} + b x + c$ . Find a pair of integers whose product is $c$ and whose sum is $b$ . In this case, whose product is $- 18$ and whose sum is $- 3$ .

$- 6, 3$

Write the factored form using these integers.

$\frac{n (m - 1) (m + 3) \cdot 2 ((m - 6) (m - 2))}{(m - 2) (m - 1) ((m - 6) (m + 3))}$

$\frac{n (m - 1) (m + 3) \cdot 2 ((m - 6) (m - 2))}{(m - 2) (m - 1) (m - 6) (m + 3)}$

Step 10

Simplify the numerator.

Rewrite.

$\frac{5 n^{2} (m^{2} + 2 m - 3) (4 n^{2} (m^{2} - 8 m + 12))}{(m - 2) (m - 1) (m - 6) (m + 3)}$

Multiply $n^{2}$ by $n^{2}$ by adding the exponents.

Move $n^{2}$ .

$\frac{5 (n^{2} n^{2}) (m^{2} + 2 m - 3) (4 (m^{2} - 8 m + 12))}{(m - 2) (m - 1) (m - 6) (m + 3)}$

Use the power rule $a^{m} a^{n} = a^{m + n}$ to combine exponents.

$\frac{5 n^{2 + 2} (m^{2} + 2 m - 3) (4 (m^{2} - 8 m + 12))}{(m - 2) (m - 1) (m - 6) (m + 3)}$

Add $2$ and $2$ .

$\frac{5 n^{4} (m^{2} + 2 m - 3) (4 (m^{2} - 8 m + 12))}{(m - 2) (m - 1) (m - 6) (m + 3)}$

Rewrite.

$\frac{n^{2} n^{2} (m^{2} + 2 m - 3) (4 (m^{2} - 8 m + 12))}{(m - 2) (m - 1) (m - 6) (m + 3)}$

Use the power rule $a^{m} a^{n} = a^{m + n}$ to combine exponents.

$\frac{n^{2 + 2} (m^{2} + 2 m - 3) (4 (m^{2} - 8 m + 12))}{(m - 2) (m - 1) (m - 6) (m + 3)}$

Add $2$ and $2$ .

$\frac{n^{4} (m^{2} + 2 m - 3) (4 (m^{2} - 8 m + 12))}{(m - 2) (m - 1) (m - 6) (m + 3)}$

Multiply $n^{4} (m^{2} + 2 m - 3)$ by $4 (m^{2} - 8 m + 12)$ .

$\frac{(n^{4} (m^{2} + 2 m - 3)) (4 (m^{2} - 8 m + 12))}{(m - 2) (m - 1) (m - 6) (m + 3)}$

Factor $n^{3}$ out of $n^{4}$ .

$\frac{n^{3} n (m^{2} + 2 m - 3) (4 (m^{2} - 8 m + 12))}{(m - 2) (m - 1) (m - 6) (m + 3)}$

Rewrite.

$\frac{n^{1} (m^{2} + 2 m - 3) (4 (m^{2} - 8 m + 12))}{(m - 2) (m - 1) (m - 6) (m + 3)}$

Simplify.

$\frac{n (m^{2} + 2 m - 3) (4 (m^{2} - 8 m + 12))}{(m - 2) (m - 1) (m - 6) (m + 3)}$

Multiply $n (m^{2} + 2 m - 3)$ by $4 (m^{2} - 8 m + 12)$ .

$\frac{(n (m^{2} + 2 m - 3)) (4 (m^{2} - 8 m + 12))}{(m - 2) (m - 1) (m - 6) (m + 3)}$

Factor $2$ out of $4$ .

$\frac{n (m^{2} + 2 m - 3) (2 (2) (m^{2} - 8 m + 12))}{(m - 2) (m - 1) (m - 6) (m + 3)}$

Rewrite.

$\frac{n (m^{2} + 2 m - 3) (\frac{4}{2} (m^{2} - 8 m + 12))}{(m - 2) (m - 1) (m - 6) (m + 3)}$

Divide $4$ by $2$ .

$\frac{n (m^{2} + 2 m - 3) (2 (m^{2} - 8 m + 12))}{(m - 2) (m - 1) (m - 6) (m + 3)}$

Multiply $2$ by $m^{2} - 8 m + 12$ .

$\frac{n (m^{2} + 2 m - 3) \cdot 2 (m^{2} - 8 m + 12)}{(m - 2) (m - 1) (m - 6) (m + 3)}$

Factor $m^{2} + 2 m - 3$ using the AC method.

Consider the form $x^{2} + b x + c$ . Find a pair of integers whose product is $c$ and whose sum is $b$ . In this case, whose product is $- 3$ and whose sum is $2$ .

$- 1, 3$

Write the factored form using these integers.

$\frac{n ((m - 1) (m + 3)) \cdot 2 (m^{2} - 8 m + 12)}{(m - 2) (m - 1) (m - 6) (m + 3)}$

$\frac{n (m - 1) (m + 3) \cdot 2 (m^{2} - 8 m + 12)}{(m - 2) (m - 1) (m - 6) (m + 3)}$

Factor $m^{2} - 8 m + 12$ using the AC method.

Consider the form $x^{2} + b x + c$ . Find a pair of integers whose product is $c$ and whose sum is $b$ . In this case, whose product is $12$ and whose sum is $- 8$ .

$- 6, - 2$

Write the factored form using these integers.

$\frac{n (m - 1) (m + 3) \cdot 2 ((m - 6) (m - 2))}{(m - 2) (m - 1) (m - 6) (m + 3)}$

Remove unnecessary parentheses.

$\frac{n (m - 1) (m + 3) \cdot 2 (m - 6) (m - 2)}{(m - 2) (m - 1) (m - 6) (m + 3)}$

Step 11

Cancel the common factor of $m - 1$ .

Cancel the common factor.

$\frac{n (m - 1) (m + 3) \cdot 2 (m - 6) (m - 2)}{(m - 2) (m - 1) (m - 6) (m + 3)}$

Rewrite the expression.

$\frac{((n (m + 3)) \cdot 2 (m - 6)) (m - 2)}{((m - 2) (m - 6)) (m + 3)}$

Step 12

Cancel the common factor of $m + 3$ .

Cancel the common factor.

$\frac{n (m + 3) \cdot 2 (m - 6) (m - 2)}{(m - 2) (m - 6) (m + 3)}$

Rewrite the expression.

$\frac{((n) \cdot 2 (m - 6)) (m - 2)}{(m - 2) (m - 6)}$

Step 13

Cancel the common factor of $m - 6$ .

Cancel the common factor.

$\frac{(n) \cdot 2 (m - 6) (m - 2)}{(m - 2) (m - 6)}$

Rewrite the expression.

$\frac{((n) \cdot 2) (m - 2)}{m - 2}$

Step 14

Cancel the common factor of $m - 2$ .

Cancel the common factor.

$\frac{(n) \cdot 2 (m - 2)}{m - 2}$

Divide $(n) \cdot 2$ by $1$ .

$(n) \cdot 2$

Step 15

Move $2$ to the left of $n$ .

$2 n$

Divide ((5n^2(m^2+2m-3))/(10n(m^2-3m+2)))÷((n^2(m^2-3m-18))/(4n^2(m^2-8m+12)))

Related Questions

Support LCMGCF.com by disabling your adblocker.