Divide (5x+6x^3-8)/(x-2)

$\frac{5 x + 6 x^{3} - 8}{x - 2}$

Step 1

Reorder $5 x$ and $6 x^{3}$ .

$\frac{6 x^{3} + 5 x - 8}{x - 2}$

Step 2

Set up the polynomials to be divided. If there is not a term for every exponent, insert one with a value of $0$ .

$x$

$2$

$6 x^{3}$

$0 x^{2}$

$5 x$

$8$

Step 3

Divide the highest order term in the dividend $6 x^{3}$ by the highest order term in divisor $x$ .

					$6 x^{2}$
	$x$	-	$2$		$6 x^{3}$	+	$0 x^{2}$	+	$5 x$	-	$8$

Step 4

Multiply the new quotient term by the divisor.

				$6 x^{2}$
$x$	-	$2$		$6 x^{3}$	+	$0 x^{2}$	+	$5 x$	-	$8$
			+	$6 x^{3}$	-	$12 x^{2}$

Step 5

The expression needs to be subtracted from the dividend, so change all the signs in $6 x^{3} - 12 x^{2}$

				$6 x^{2}$
$x$	-	$2$		$6 x^{3}$	+	$0 x^{2}$	+	$5 x$	-	$8$
			-	$6 x^{3}$	+	$12 x^{2}$

Step 6

After changing the signs, add the last dividend from the multiplied polynomial to find the new dividend.

				$6 x^{2}$
$x$	-	$2$		$6 x^{3}$	+	$0 x^{2}$	+	$5 x$	-	$8$
			-	$6 x^{3}$	+	$12 x^{2}$
					+	$12 x^{2}$

Step 7

Pull the next terms from the original dividend down into the current dividend.

				$6 x^{2}$
$x$	-	$2$		$6 x^{3}$	+	$0 x^{2}$	+	$5 x$	-	$8$
			-	$6 x^{3}$	+	$12 x^{2}$
					+	$12 x^{2}$	+	$5 x$

Step 8

Divide the highest order term in the dividend $12 x^{2}$ by the highest order term in divisor $x$ .

				$6 x^{2}$	+	$12 x$
$x$	-	$2$		$6 x^{3}$	+	$0 x^{2}$	+	$5 x$	-	$8$
			-	$6 x^{3}$	+	$12 x^{2}$
					+	$12 x^{2}$	+	$5 x$

Step 9

Multiply the new quotient term by the divisor.

				$6 x^{2}$	+	$12 x$
$x$	-	$2$		$6 x^{3}$	+	$0 x^{2}$	+	$5 x$	-	$8$
			-	$6 x^{3}$	+	$12 x^{2}$
					+	$12 x^{2}$	+	$5 x$
					+	$12 x^{2}$	-	$24 x$

Step 10

The expression needs to be subtracted from the dividend, so change all the signs in $12 x^{2} - 24 x$

				$6 x^{2}$	+	$12 x$
$x$	-	$2$		$6 x^{3}$	+	$0 x^{2}$	+	$5 x$	-	$8$
			-	$6 x^{3}$	+	$12 x^{2}$
					+	$12 x^{2}$	+	$5 x$
					-	$12 x^{2}$	+	$24 x$

Step 11

After changing the signs, add the last dividend from the multiplied polynomial to find the new dividend.

				$6 x^{2}$	+	$12 x$
$x$	-	$2$		$6 x^{3}$	+	$0 x^{2}$	+	$5 x$	-	$8$
			-	$6 x^{3}$	+	$12 x^{2}$
					+	$12 x^{2}$	+	$5 x$
					-	$12 x^{2}$	+	$24 x$
							+	$29 x$

Step 12

Pull the next terms from the original dividend down into the current dividend.

				$6 x^{2}$	+	$12 x$
$x$	-	$2$		$6 x^{3}$	+	$0 x^{2}$	+	$5 x$	-	$8$
			-	$6 x^{3}$	+	$12 x^{2}$
					+	$12 x^{2}$	+	$5 x$
					-	$12 x^{2}$	+	$24 x$
							+	$29 x$	-	$8$

Step 13

Divide the highest order term in the dividend $29 x$ by the highest order term in divisor $x$ .

				$6 x^{2}$	+	$12 x$	+	$29$
$x$	-	$2$		$6 x^{3}$	+	$0 x^{2}$	+	$5 x$	-	$8$
			-	$6 x^{3}$	+	$12 x^{2}$
					+	$12 x^{2}$	+	$5 x$
					-	$12 x^{2}$	+	$24 x$
							+	$29 x$	-	$8$

Step 14

Multiply the new quotient term by the divisor.

				$6 x^{2}$	+	$12 x$	+	$29$
$x$	-	$2$		$6 x^{3}$	+	$0 x^{2}$	+	$5 x$	-	$8$
			-	$6 x^{3}$	+	$12 x^{2}$
					+	$12 x^{2}$	+	$5 x$
					-	$12 x^{2}$	+	$24 x$
							+	$29 x$	-	$8$
							+	$29 x$	-	$58$

Step 15

The expression needs to be subtracted from the dividend, so change all the signs in $29 x - 58$

				$6 x^{2}$	+	$12 x$	+	$29$
$x$	-	$2$		$6 x^{3}$	+	$0 x^{2}$	+	$5 x$	-	$8$
			-	$6 x^{3}$	+	$12 x^{2}$
					+	$12 x^{2}$	+	$5 x$
					-	$12 x^{2}$	+	$24 x$
							+	$29 x$	-	$8$
							-	$29 x$	+	$58$

Step 16

After changing the signs, add the last dividend from the multiplied polynomial to find the new dividend.

				$6 x^{2}$	+	$12 x$	+	$29$
$x$	-	$2$		$6 x^{3}$	+	$0 x^{2}$	+	$5 x$	-	$8$
			-	$6 x^{3}$	+	$12 x^{2}$
					+	$12 x^{2}$	+	$5 x$
					-	$12 x^{2}$	+	$24 x$
							+	$29 x$	-	$8$
							-	$29 x$	+	$58$
									+	$50$

Step 17

The final answer is the quotient plus the remainder over the divisor.

$6 x^{2} + 12 x + 29 + \frac{50}{x - 2}$

Divide (5x+6x^3-8)/(x-2)

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