Divide (6-3 cube root of 6)/( cube root of 9)

$\frac{6 - 3 \sqrt[3]{6}}{\sqrt[3]{9}}$

Step 1

Multiply $\frac{6 - 3 \sqrt[3]{6}}{\sqrt[3]{9}}$ by $\frac{{\sqrt[3]{9}}^{2}}{{\sqrt[3]{9}}^{2}}$ .

$\frac{6 - 3 \sqrt[3]{6}}{\sqrt[3]{9}} \cdot \frac{{\sqrt[3]{9}}^{2}}{{\sqrt[3]{9}}^{2}}$

Step 2

Combine and simplify the denominator.

Multiply $\frac{6 - 3 \sqrt[3]{6}}{\sqrt[3]{9}}$ by $\frac{{\sqrt[3]{9}}^{2}}{{\sqrt[3]{9}}^{2}}$ .

$\frac{(6 - 3 \sqrt[3]{6}) {\sqrt[3]{9}}^{2}}{\sqrt[3]{9} {\sqrt[3]{9}}^{2}}$

Raise $\sqrt[3]{9}$ to the power of $1$ .

$\frac{(6 - 3 \sqrt[3]{6}) {\sqrt[3]{9}}^{2}}{{\sqrt[3]{9}}^{1} {\sqrt[3]{9}}^{2}}$

Use the power rule $a^{m} a^{n} = a^{m + n}$ to combine exponents.

$\frac{(6 - 3 \sqrt[3]{6}) {\sqrt[3]{9}}^{2}}{{\sqrt[3]{9}}^{1 + 2}}$

Add $1$ and $2$ .

$\frac{(6 - 3 \sqrt[3]{6}) {\sqrt[3]{9}}^{2}}{{\sqrt[3]{9}}^{3}}$

Rewrite ${\sqrt[3]{9}}^{3}$ as $9$ .

Use $\sqrt[n]{a^{x}} = a^{\frac{x}{n}}$ to rewrite $\sqrt[3]{9}$ as $9^{\frac{1}{3}}$ .

$\frac{(6 - 3 \sqrt[3]{6}) {\sqrt[3]{9}}^{2}}{{(9^{\frac{1}{3}})}^{3}}$

Apply the power rule and multiply exponents, ${(a^{m})}^{n} = a^{m n}$ .

$\frac{(6 - 3 \sqrt[3]{6}) {\sqrt[3]{9}}^{2}}{9^{\frac{1}{3} \cdot 3}}$

Combine $\frac{1}{3}$ and $3$ .

$\frac{(6 - 3 \sqrt[3]{6}) {\sqrt[3]{9}}^{2}}{9^{\frac{3}{3}}}$

Cancel the common factor of $3$ .

Cancel the common factor.

$\frac{(6 - 3 \sqrt[3]{6}) {\sqrt[3]{9}}^{2}}{9^{\frac{3}{3}}}$

Rewrite the expression.

$\frac{(6 - 3 \sqrt[3]{6}) {\sqrt[3]{9}}^{2}}{9^{1}}$

Evaluate the exponent.

$\frac{(6 - 3 \sqrt[3]{6}) {\sqrt[3]{9}}^{2}}{9}$

Step 3

Cancel the common factor of $6 - 3 \sqrt[3]{6}$ and $9$ .

Factor $3$ out of $(6 - 3 \sqrt[3]{6}) {\sqrt[3]{9}}^{2}$ .

$\frac{3 ((2 - \sqrt[3]{6}) {\sqrt[3]{9}}^{2})}{9}$

Cancel the common factors.

Factor $3$ out of $9$ .

$\frac{3 ((2 - \sqrt[3]{6}) {\sqrt[3]{9}}^{2})}{3 (3)}$

Cancel the common factor.

$\frac{3 ((2 - \sqrt[3]{6}) {\sqrt[3]{9}}^{2})}{3 \cdot 3}$

Rewrite the expression.

$\frac{(2 - \sqrt[3]{6}) {\sqrt[3]{9}}^{2}}{3}$

Step 4

Simplify the numerator.

Rewrite ${\sqrt[3]{9}}^{2}$ as ${(9^{2})}^{\frac{1}{3}}$ .

$\frac{(2 - \sqrt[3]{6}) \sqrt[3]{9^{2}}}{3}$

Raise $9$ to the power of $2$ .

$\frac{(2 - \sqrt[3]{6}) \sqrt[3]{81}}{3}$

Rewrite $81$ as $3^{3} \cdot 3$ .

Factor $27$ out of $81$ .

$\frac{(2 - \sqrt[3]{6}) \sqrt[3]{27 (3)}}{3}$

Rewrite $27$ as $3^{3}$ .

$\frac{(2 - \sqrt[3]{6}) \sqrt[3]{3^{3} \cdot 3}}{3}$

Pull terms out from under the radical.

$\frac{(2 - \sqrt[3]{6}) \cdot 3 \sqrt[3]{3}}{3}$

Step 5

Cancel the common factor of $3$ .

Cancel the common factor.

$\frac{(2 - \sqrt[3]{6}) \cdot 3 \sqrt[3]{3}}{3}$

Divide $(2 - \sqrt[3]{6}) \sqrt[3]{3}$ by $1$ .

$(2 - \sqrt[3]{6}) \sqrt[3]{3}$

Step 6

Apply the distributive property.

$2 \sqrt[3]{3} - \sqrt[3]{6} \sqrt[3]{3}$

Step 7

Multiply $- \sqrt[3]{6} \sqrt[3]{3}$ .

Combine using the product rule for radicals.

$2 \sqrt[3]{3} - \sqrt[3]{3 \cdot 6}$

Multiply $3$ by $6$ .

$2 \sqrt[3]{3} - \sqrt[3]{18}$

Step 8

The result can be shown in multiple forms.

Exact Form:

$2 \sqrt[3]{3} - \sqrt[3]{18}$

Decimal Form:

$0.26375774 \dots$

Divide (6-3 cube root of 6)/( cube root of 9)

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