Divide (6x^3+12-47x^2+17x)÷(6x-5)


Step 1
Expand .

Move .
Move .

Step 2
Set up the polynomials to be divided. If there is not a term for every exponent, insert one with a value of .
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Step 3
Divide the highest order term in the dividend by the highest order term in divisor .
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Step 4
Multiply the new quotient term by the divisor.
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Step 5
The expression needs to be subtracted from the dividend, so change all the signs in
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-+

Step 6
After changing the signs, add the last dividend from the multiplied polynomial to find the new dividend.
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-+
-

Step 7
Pull the next terms from the original dividend down into the current dividend.
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-+

Step 8
Divide the highest order term in the dividend by the highest order term in divisor .
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--++
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-+

Step 9
Multiply the new quotient term by the divisor.
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--++
-+
-+
-+

Step 10
The expression needs to be subtracted from the dividend, so change all the signs in
-
--++
-+
-+
+-

Step 11
After changing the signs, add the last dividend from the multiplied polynomial to find the new dividend.
-
--++
-+
-+
+-
-

Step 12
Pull the next terms from the original dividend down into the current dividend.
-
--++
-+
-+
+-
-+

Step 13
Divide the highest order term in the dividend by the highest order term in divisor .
--
--++
-+
-+
+-
-+

Step 14
Multiply the new quotient term by the divisor.
--
--++
-+
-+
+-
-+
-+

Step 15
The expression needs to be subtracted from the dividend, so change all the signs in
--
--++
-+
-+
+-
-+
+-

Step 16
After changing the signs, add the last dividend from the multiplied polynomial to find the new dividend.
--
--++
-+
-+
+-
-+
+-
-

Step 17
The final answer is the quotient plus the remainder over the divisor.


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