Divide (6y^2-5y-15)(2y+3)^-1

$(6 y^{2} - 5 y - 15) {(2 y + 3)}^{- 1}$

Rewrite the expression using the negative exponent rule $b^{- n} = \frac{1}{b^{n}}$ .

$(6 y^{2} - 5 y - 15) \frac{1}{2 y + 3}$