Divide 9/(-i)

$\frac{9}{- i}$

Step 1

Multiply the numerator and denominator of $\frac{9}{- i}$ by the conjugate of $- i$ to make the denominator real.

$\frac{9}{- i} \cdot \frac{i}{i}$

Step 2

Multiply.

Combine.

$\frac{9 i}{- i i}$

Simplify the denominator.

Add parentheses.

$\frac{9 i}{- (i i)}$

Raise $i$ to the power of $1$ .

$\frac{9 i}{- (i^{1} i)}$

Raise $i$ to the power of $1$ .

$\frac{9 i}{- (i^{1} i^{1})}$

Use the power rule $a^{m} a^{n} = a^{m + n}$ to combine exponents.

$\frac{9 i}{- i^{1 + 1}}$

Add $1$ and $1$ .

$\frac{9 i}{- i^{2}}$

Rewrite $i^{2}$ as $- 1$ .

$\frac{9 i}{- - 1}$

Step 3

Multiply $- 1$ by $- 1$ .

$\frac{9 i}{1}$

Step 4

Divide $9 i$ by $1$ .

$9 i$