Divide (9n^3+n^2+3n)/(9n^2)

$\frac{9 n^{3} + n^{2} + 3 n}{9 n^{2}}$

Step 1

Factor $n$ out of $9 n^{3} + n^{2} + 3 n$ .

Factor $n$ out of $9 n^{3}$ .

$\frac{n (9 n^{2}) + n^{2} + 3 n}{9 n^{2}}$

Factor $n$ out of $n^{2}$ .

$\frac{n (9 n^{2}) + n \cdot n + 3 n}{9 n^{2}}$

Factor $n$ out of $3 n$ .

$\frac{n (9 n^{2}) + n \cdot n + n \cdot 3}{9 n^{2}}$

Factor $n$ out of $n (9 n^{2}) + n \cdot n$ .

$\frac{n (9 n^{2} + n) + n \cdot 3}{9 n^{2}}$

Factor $n$ out of $n (9 n^{2} + n) + n \cdot 3$ .

$\frac{n (9 n^{2} + n + 3)}{9 n^{2}}$

Step 2

Cancel the common factors.

Factor $n$ out of $9 n^{2}$ .

$\frac{n (9 n^{2} + n + 3)}{n (9 n)}$

Cancel the common factor.

$\frac{n (9 n^{2} + n + 3)}{n (9 n)}$

Rewrite the expression.

$\frac{9 n^{2} + n + 3}{9 n}$

Step 3

Split the fraction $\frac{9 n^{2} + n + 3}{9 n}$ into two fractions.

$\frac{9 n^{2} + n}{9 n} + \frac{3}{9 n}$

Step 4

Split the fraction $\frac{9 n^{2} + n}{9 n}$ into two fractions.

$\frac{9 n^{2}}{9 n} + \frac{n}{9 n} + \frac{3}{9 n}$

Step 5

Cancel the common factor of $9$ .

Cancel the common factor.

$\frac{9 n^{2}}{9 n} + \frac{n}{9 n} + \frac{3}{9 n}$

Rewrite the expression.

$\frac{n^{2}}{n} + \frac{n}{9 n} + \frac{3}{9 n}$

Step 6

Cancel the common factor of $n^{2}$ and $n$ .

Factor $n$ out of $n^{2}$ .

$\frac{n \cdot n}{n} + \frac{n}{9 n} + \frac{3}{9 n}$

Cancel the common factors.

Raise $n$ to the power of $1$ .

$\frac{n \cdot n}{n^{1}} + \frac{n}{9 n} + \frac{3}{9 n}$

Factor $n$ out of $n^{1}$ .

$\frac{n \cdot n}{n \cdot 1} + \frac{n}{9 n} + \frac{3}{9 n}$

Cancel the common factor.

$\frac{n \cdot n}{n \cdot 1} + \frac{n}{9 n} + \frac{3}{9 n}$

Rewrite the expression.

$\frac{n}{1} + \frac{n}{9 n} + \frac{3}{9 n}$

Divide $n$ by $1$ .

$n + \frac{n}{9 n} + \frac{3}{9 n}$

Step 7

Cancel the common factor of $n$ .

Cancel the common factor.

$n + \frac{n}{9 n} + \frac{3}{9 n}$

Rewrite the expression.

$n + \frac{1}{9} + \frac{3}{9 n}$

Step 8

Cancel the common factor of $3$ and $9$ .

Factor $3$ out of $3$ .

$n + \frac{1}{9} + \frac{3 (1)}{9 n}$

Cancel the common factors.

Factor $3$ out of $9 n$ .

$n + \frac{1}{9} + \frac{3 (1)}{3 (3 n)}$

Cancel the common factor.

$n + \frac{1}{9} + \frac{3 \cdot 1}{3 (3 n)}$

Rewrite the expression.

$n + \frac{1}{9} + \frac{1}{3 n}$

Divide (9n^3+n^2+3n)/(9n^2)

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