Divide (a^4+4b^4)÷(a^2-2ab+2b^2)

$(a^{4} + 4 b^{4}) \div (a^{2} - 2 a b + 2 b^{2})$

Step 1

Rewrite the division as a fraction.

$\frac{a^{4} + 4 b^{4}}{a^{2} - 2 a b + 2 b^{2}}$

Step 2

Split the fraction $\frac{a^{4} + 4 b^{4}}{a^{2} - 2 a b + 2 b^{2}}$ into two fractions.

$\frac{a^{4}}{a^{2} - 2 a b + 2 b^{2}} + \frac{4 b^{4}}{a^{2} - 2 a b + 2 b^{2}}$