Divide (n^2+6n+5)/(n+1)

$\frac{n^{2} + 6 n + 5}{n + 1}$

Step 1

Factor $n^{2} + 6 n + 5$ using the AC method.

Consider the form $x^{2} + b x + c$ . Find a pair of integers whose product is $c$ and whose sum is $b$ . In this case, whose product is $5$ and whose sum is $6$ .

$1, 5$

Write the factored form using these integers.

$\frac{(n + 1) (n + 5)}{n + 1}$

Step 2

Cancel the common factor of $n + 1$ .

Cancel the common factor.

$\frac{(n + 1) (n + 5)}{n + 1}$

Divide $n + 5$ by $1$ .

$n + 5$

Divide (n^2+6n+5)/(n+1)

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