Divide ( sixth root of 4)÷( cube root of 3)

$\sqrt[6]{4} \div \sqrt[3]{3}$

Rewrite the division as a fraction.

$\frac{\sqrt[6]{4}}{\sqrt[3]{3}}$

Simplify the numerator.

Rewrite $4$ as $2^{2}$ .

$\frac{\sqrt[6]{2^{2}}}{\sqrt[3]{3}}$

Rewrite $\sqrt[6]{2^{2}}$ as $\sqrt[3]{\sqrt{2^{2}}}$ .

$\frac{\sqrt[3]{\sqrt{2^{2}}}}{\sqrt[3]{3}}$

Pull terms out from under the radical, assuming positive real numbers.

$\frac{\sqrt[3]{2}}{\sqrt[3]{3}}$

Multiply $\frac{\sqrt[3]{2}}{\sqrt[3]{3}}$ by $\frac{{\sqrt[3]{3}}^{2}}{{\sqrt[3]{3}}^{2}}$ .

$\frac{\sqrt[3]{2}}{\sqrt[3]{3}} \cdot \frac{{\sqrt[3]{3}}^{2}}{{\sqrt[3]{3}}^{2}}$

Combine and simplify the denominator.

Multiply $\frac{\sqrt[3]{2}}{\sqrt[3]{3}}$ by $\frac{{\sqrt[3]{3}}^{2}}{{\sqrt[3]{3}}^{2}}$ .

$\frac{\sqrt[3]{2} {\sqrt[3]{3}}^{2}}{\sqrt[3]{3} {\sqrt[3]{3}}^{2}}$

Raise $\sqrt[3]{3}$ to the power of $1$ .

$\frac{\sqrt[3]{2} {\sqrt[3]{3}}^{2}}{{\sqrt[3]{3}}^{1} {\sqrt[3]{3}}^{2}}$

Use the power rule $a^{m} a^{n} = a^{m + n}$ to combine exponents.

$\frac{\sqrt[3]{2} {\sqrt[3]{3}}^{2}}{{\sqrt[3]{3}}^{1 + 2}}$

Add $1$ and $2$ .

$\frac{\sqrt[3]{2} {\sqrt[3]{3}}^{2}}{{\sqrt[3]{3}}^{3}}$

Rewrite ${\sqrt[3]{3}}^{3}$ as $3$ .

Use $\sqrt[n]{a^{x}} = a^{\frac{x}{n}}$ to rewrite $\sqrt[3]{3}$ as $3^{\frac{1}{3}}$ .

$\frac{\sqrt[3]{2} {\sqrt[3]{3}}^{2}}{{(3^{\frac{1}{3}})}^{3}}$

Apply the power rule and multiply exponents, ${(a^{m})}^{n} = a^{m n}$ .

$\frac{\sqrt[3]{2} {\sqrt[3]{3}}^{2}}{3^{\frac{1}{3} \cdot 3}}$

Combine $\frac{1}{3}$ and $3$ .

$\frac{\sqrt[3]{2} {\sqrt[3]{3}}^{2}}{3^{\frac{3}{3}}}$

Cancel the common factor of $3$ .

Cancel the common factor.

$\frac{\sqrt[3]{2} {\sqrt[3]{3}}^{2}}{3^{\frac{3}{3}}}$

Rewrite the expression.

$\frac{\sqrt[3]{2} {\sqrt[3]{3}}^{2}}{3^{1}}$

Evaluate the exponent.

$\frac{\sqrt[3]{2} {\sqrt[3]{3}}^{2}}{3}$

Simplify the numerator.

Rewrite ${\sqrt[3]{3}}^{2}$ as ${(3^{2})}^{\frac{1}{3}}$ .

$\frac{\sqrt[3]{2} \sqrt[3]{3^{2}}}{3}$

Raise $3$ to the power of $2$ .

$\frac{\sqrt[3]{2} \sqrt[3]{9}}{3}$

Simplify the numerator.

Combine using the product rule for radicals.

$\frac{\sqrt[3]{2 \cdot 9}}{3}$

Multiply $2$ by $9$ .

$\frac{\sqrt[3]{18}}{3}$

The result can be shown in multiple forms.

Exact Form:

$\frac{\sqrt[3]{18}}{3}$

Decimal Form:

$0.87358046 \dots$

Divide ( sixth root of 4)÷( cube root of 3)

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