Divide Using Long Polynomial Division (x^3-3x^2+x-2)÷(10x^4-14x^3-10x^2+6x-10)

$(x^{3} - 3 x^{2} + x - 2) \div (10 x^{4} - 14 x^{3} - 10 x^{2} + 6 x - 10)$

Step 1

Set up the polynomials to be divided. If there is not a term for every exponent, insert one with a value of $0$ .

$10 x^{4}$

$14 x^{3}$

$10 x^{2}$

$6 x$

$10$

$x^{3}$

$3 x^{2}$

$x$

$2$

Step 2

The final answer is the quotient plus the remainder over the divisor.

$0 + \frac{10 x^{4} - 13 x^{3} - 13 x^{2} + 7 x - 12}{10 x^{4} - 14 x^{3} - 10 x^{2} + 6 x - 10}$